Hi
I want to sum of 3 columns in file.
Example: I want to sum of 3 ,6,8 th columns in file(SUM(3,6,8)).
Using awk can sum of single column
awk '{a+=$3} END {printf ("%f\n",a)' file_name
Thanks inadvance
MR (2 Replies)
Hello everyone I need to write a script that sums numbers passed to it as arguments on the command line and displays the results. I must use a for loop and then rewrite it using a while loop. It would have to output something like 10+20+30=60
this is what I have so far
fafountain@hfc:~$ vi sum... (1 Reply)
Hi
i data looks like this:
student 1
Subject1 45 55
Subject2 44 55
Subject3 33 44
//
student 2
Subject1 45 55
Subject2 44 55
Subject3 33 44
i would like to sum $2, $3 (marks) and divide each entry in $2 and $3 with their respective sums and print for each student as $4 and... (2 Replies)
Hi
I need to incorporate a 'sum' as follows into a script and not sure how. I have a variable per line and I need them to be summed, e.g below
1
23
1,456
1
1
34
46
How do I calculate the sum of all these numbers to ouptut the answer ( 1,562)
Thanks in advance (3 Replies)
I am trying to get the sum of the first column of a file. When I use the same method for other files it works just fine... for some reason for the file below it gives me an error that I don't understand... I tried looking at different lines of the file and tried different things, but I still... (7 Replies)
Hi, Unix Gurus,
I need sum values from a file. file format like:
0004004
0000817
0045000
0045000
0045000
0045000
0045000
0045000
0045000
0045000
0045000
0045000
0004406
the result should be 459227 (817+45000 ... + 4406)
anybody can help me out (7 Replies)
I have a list of values ( in Kb) I have the following code to sum up the values and convert the total to GB
cat list
701368101370
101370101370
801554101370
701636101370
101757101370
101876101370
901951101370
And this is the output of my script
awk '{ s += $1 } END {... (3 Replies)
Hi Friends,
I have a file with fields separated with comma. How to print sum of each field of the file?
Eg:
input file
1,3,6,7
2,1,2,1
0,1,1,0
I want to sum each field separately.
Output file
3,5,9,8
Thanks,
Suresh (2 Replies)
HI Guys,
I gave Input file F.Txt
ID H1 H2 H3 H4 H5
A 5 6 7 8 9
B 4 65 4 4 7
C 4 4 4 4 4
D 4 4 4 4 4
Output :-
ID H1 H2 H3 H4 H5
Total 17 79 19 20 24
Sum of Each Columns (8 Replies)
Discussion started by: pareshkp
8 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)