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Full Discussion: Command to pull date
Top Forums Shell Programming and Scripting Command to pull date Post 302952282 by anshu ranjan on Monday 17th of August 2015 03:52:23 AM
Old 08-17-2015
Command to pull date

I have one file with below entry. There are multiple entries, but for sample I used just three lines.
my requirment is to create a script by which it will pull only those entries which modification time is greater than 2 weeks (or 15 days). if I run script today, it will compare date from today and pull entriies which modification time is greater than 2 weeks.
Is there any command or combination of commands which can be used for this activity?

Input
Code:
Login = user1
Modification Time = July 27, 2015 4:57:55 AM EDT
Login = user2
Modification Time = June 24, 2015 5:39:23 AM EDT
Login = user3
Modification Time = Aug 5, 2015 4:53:53 AM EDT

Required Output
Code:
Login = user1
Modification Time = July 27, 2015 4:57:55 AM EDT
Login = user2
Modification Time = June 24, 2015 5:39:23 AM EDT

Below is Output of date command in my server
Code:
> date
Mon Aug 17 03:46:31 EDT 2015


Last edited by vbe; 08-17-2015 at 05:35 AM.. Reason: code tags please. not HTML...
 

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Time::Seconds(3pm)					 Perl Programmers Reference Guide					Time::Seconds(3pm)

NAME
Time::Seconds - a simple API to convert seconds to other date values SYNOPSIS
use Time::Piece; use Time::Seconds; my $t = localtime; $t += ONE_DAY; my $t2 = localtime; my $s = $t - $t2; print "Difference is: ", $s->days, " "; DESCRIPTION
This module is part of the Time::Piece distribution. It allows the user to find out the number of minutes, hours, days, weeks or years in a given number of seconds. It is returned by Time::Piece when you delta two Time::Piece objects. Time::Seconds also exports the following constants: ONE_DAY ONE_WEEK ONE_HOUR ONE_MINUTE ONE_MONTH ONE_YEAR ONE_FINANCIAL_MONTH LEAP_YEAR NON_LEAP_YEAR Since perl does not (yet?) support constant objects, these constants are in seconds only, so you cannot, for example, do this: "print ONE_WEEK->minutes;" METHODS
The following methods are available: my $val = Time::Seconds->new(SECONDS) $val->seconds; $val->minutes; $val->hours; $val->days; $val->weeks; $val->months; $val->financial_months; # 30 days $val->years; The methods make the assumption that there are 24 hours in a day, 7 days in a week, 365.24225 days in a year and 12 months in a year. (from The Calendar FAQ at http://www.tondering.dk/claus/calendar.html) AUTHOR
Matt Sergeant, matt@sergeant.org Tobias Brox, tobiasb@tobiasb.funcom.com BalieXXzs SzabieXX (dLux), dlux@kapu.hu LICENSE
Please see Time::Piece for the license. Bugs Currently the methods aren't as efficient as they could be, for reasons of clarity. This is probably a bad idea. perl v5.12.1 2010-04-26 Time::Seconds(3pm)
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