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Full Discussion: Clipping -awk
Top Forums UNIX for Dummies Questions & Answers Clipping -awk Post 302948837 by Xterra on Thursday 2nd of July 2015 10:28:24 PM
Old 07-02-2015
Don
I apologize -in my defense, English is not my mother tongue, not an excuse just and explanation.
You see, the input file is a DNA alignment. The aligment tool (mafft), aligns each nucleotide (ATGC) in all sequences (multiple alignment). If one of the sequences is shorter, like the Reference in my example above, the alignment tool adds hyphens at the ends. I need to find the References sequence and scan it till I find the first nucleotide, in this case "a", and cut all sequences at that nucleotide position. Then, I must scan the Reference sequence till I find the last nucleotide, in this case another "a", and cut all sequences at that very same position. Thus, all sequences will have the same length. Sometimes, the DNA sequences have mismatches at the ends maki g nearly impossible to trim them based on a nucleotide pattern -mafft takes care of that since mutations do not disturbe the alignment.
I hope this explains better what I am trying to accomplish
Thanks!
PS. The reference does not contain gaps (hyphens) in between nucleotides. Thus, the string of hyphens in the flanks mark the beggining and end of the reference sequence
 

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bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
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