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Top Forums Shell Programming and Scripting Swapping the 1st 4 lines only Post 302947350 by RavinderSingh13 on Wednesday 17th of June 2015 11:07:30 AM
Old 06-17-2015
Hello invinzin21,

Following is explanation for same code, hope this will be helpful.
Code:
 awk '{if(NR==1 || NR==2 || NR==3 || NR==4){A=A?A ORS $0:$0;next};if(NR==8){print $0 ORS A;} else {print}}'  Input_file
 if(NR==1 || NR==2 || NR==3 || NR==4)  #### Looking for condition if line number is equal to 1 or 2 or 3 or 4
{A=A?A ORS $0:$0;next}                          #### If above condition is TRUE then I am creating a variable which will hold the 
 current line's value with it's previouls value character ? is to perform a action when condition before will be TRUE and : is used to perform action when condition is FALSE.
next                                                         #### After above variable's creation leave next statements and move next
 if(NR==8)                                               #### Looking for condition when line number is 8
{print $0 ORS A;}                                    #### if above condition is TRUE then print the 8th line and print variable A, which has now value of lines from 1 to 4 in it
else                                                         #### Apart of any line pther than 8 it will do simple print operation.

Thanks,
R. Singh

Last edited by RavinderSingh13; 06-17-2015 at 12:13 PM.. Reason: Sorry for aligning not sure why I am always not able to align text properly, may be copying from notepad, sorry for same.
 

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bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
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