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Full Discussion: Ls -ltr in scripting
Top Forums Shell Programming and Scripting Ls -ltr in scripting Post 302947019 by Don Cragun on Sunday 14th of June 2015 05:56:53 PM
Old 06-14-2015
Quote:
Originally Posted by Aia
Code:
printf "List of files %s\n" $(ls -ltr)

List of files total 12
List of files -rw-rw-r--. 1 aia aia  148 Jun  7 19:49 index.html
List of files -rw-rw-r--. 1 aia aia 1446 Jun 12 20:27 pvz.html
List of files -rw-rw-r--. 1 aia aia 1984 Jun 13 22:50 pvz.bgcolor.html
List of files drwxrwxr-x. 2 aia aia   23 Jun 14 12:06 pvz

Expanding on what Scrutinizer said... As already explained in this thread, this only works if IFS is set to the <newline> character.

With a default setting of IFS (IFS=$' \t\n'), that command would produce something more like:
Code:
List of files total
List of filesl 12
List of files -rw-rw-r--.
List of files 1
List of files aia
List of files aia
List of files 148
List of files Jun
List of files 7
List of files 19:49
List of files index.html
... ... ...

And, you get the same results with:
Code:
IFS=$'\n' printf "List of files %s\n" $(ls -ltr)

because that only sets IFS in the environment for the invocation of printf; not for the evaluation of the results of the command substitution done in the current shell execution environment when preparing arguments to be passed to printf.

Last edited by Don Cragun; 06-14-2015 at 06:57 PM.. Reason: Add note...
 

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bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
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