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Full Discussion: Improve script and get new output file
Top Forums Shell Programming and Scripting Improve script and get new output file Post 302946996 by RudiC on Sunday 14th of June 2015 07:23:52 AM
Old 06-14-2015
With not inconsiderable guesswork I tried to reconstruct the underlying file structure for four files:
Code:
spread_1.x01
spread_2.x01
spread_3.x01
spread_4.x01
1offb1-Sx.sps
2offb1-Sx.sps
3offb1-Sx.sps
4offb1-Sx.sps

Is that close to reality? If yes, this bash script might do what you need

Code:
#!/bin/bash
read -p "from: " fsw
read -p "to  : " lsw

awk '
FNR==1          {delete CHGARR 
                 swath=FILENAME
                 sub (/^.*_/,  "", swath)
                 sub (/\..*$/, "", swath)
                 while (1 == getline LINE < (swath"offb1-Sx.sps"))
                        {split (LINE, TMP)
                         CHGARR[TMP[5]]=TMP[1]
                        }
                }

                {IX = (int($4) int($5))}

IX in CHGARR    {sub ($4, sprintf("%8.2f",  substr(CHGARR[IX], 2, 5)))
                 sub ($5, sprintf("%8.2f3", substr(CHGARR[IX], 7, 5)))
                }

                {print $0 > FILENAME".new"}

' $(eval echo spread_{$fsw..$lsw}.x01)

Please be aware that {$fsw..$lsw} is a bashism and does not necessarily exist in other shells.

If fsw and lsw are single digit numbers only, you could simplify the file selection to spread_[$fsw-$lsw].x01


Results: with the change file 1offb1-Sx.sps (file2)
Code:
S5458920611 480873.0   2556515.5                           1.7  5458920593 2611 000 Ex

, the line from data file spread_1.x01 (file1)
Code:
X     0       01   54589.00  20593.001 1793 18681  54764.00  20626.00  20776.001

becomes spread_1.x01.new
Code:
X     0       01   54589.00  20611.003 1793 18681  54764.00  20626.00  20776.001

Give it a shot and report back.
Last edited by RudiC; 06-14-2015 at 10:25 AM..
This User Gave Thanks to RudiC For This Post:
jiam912
 

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