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Top Forums Shell Programming and Scripting Hundreds of files need manual preparation. Does shell script could do it automatically? Post 302945649 by gandolf989 on Monday 1st of June 2015 09:34:04 AM
Old 06-01-2015
This might be the long way of getting it done. But it seems to work.
You can put it into a for loop if you need to process each value.

Code:
cat feco4_s.log.txt | grep -v '[A-Z]' | grep -v '[a-z]' | grep '[0-9]\.[0-9]'

 

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ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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