Sponsored Content
Top Forums Shell Programming and Scripting Getting syntax error with awk ternary operator Post 302942146 by disedorgue on Friday 24th of April 2015 05:20:56 PM
Old 04-24-2015
Hi,
ternary operator is:
Code:
Condition ? one and only one true expr : one and only one false expr

you must have false expr also:
Code:
hour >= 12? amPm=" PM" : amPm=" AM"
hour >= 12? hour = hour - 12 : 0
hour == 0? hour = 12 : 0

Regards.
This User Gave Thanks to disedorgue For This Post:
 

10 More Discussions You Might Find Interesting

1. Programming

ternary operator

How do I interpret the following ternary operation? fn_max(var_type a,var_type b,var_type c) { var_type t; return(t=((t>a?:t;a)>b)?:t;b)>c?:t;c) } Thanks (1 Reply)
Discussion started by: naan
1 Replies

2. UNIX for Dummies Questions & Answers

'awk' syntax error

Due to some syntax error, my below code is not working. #!/usr/bin/ksh nawk ' BEGIN { cur_val=0; cur_zero=0; cur_nine=0; sum_zero=0; sum_nine=0; } /^/ { cur_val=substr($0,5,2); if("cur_val" == "0") { ... (3 Replies)
Discussion started by: lokiman
3 Replies

3. UNIX for Dummies Questions & Answers

awk Shell Script error : "Syntax Error : `Split' unexpected

hi there i write one awk script file in shell programing the code is related to dd/mm/yy to month, day year format but i get an error please can anybody help me out in this problem ?????? i give my code here including error awk ` # date-month -- convert mm/dd/yy to month day,... (2 Replies)
Discussion started by: Herry
2 Replies

4. Shell Programming and Scripting

syntax error: `-a' unexpected operator/operand in IF

When i tyr this, it gives me a syntax error...i tried removing quotes,removing spaces,replacing -eq with '='.. Can somebody suggest that is the problem? if ]; then (4 Replies)
Discussion started by: dba.admin2008
4 Replies

5. Shell Programming and Scripting

syntax error in shell test: unknown operator

Hi All, can some one figure out the syntax issue here. How to overcome this? #!/bin/sh $ HFR_MAIL=NO $ PRP_MAIL=NO $ MC_MAIL=NO $ if && && ]; then > echo "NO " > else > echo "YES" > fi test: unknown operator NO $ if && && ]; then > echo "NO" > else > echo "YES" >... (4 Replies)
Discussion started by: shellscripter
4 Replies

6. Shell Programming and Scripting

zsh ternary operator syntax help

Hi, Can someone give me an example of how to use zsh's ternary operator? I tried: # a=1 # c=( a ? "true" : "false" ) and got: zsh: no matches found: ? I'm running zsh 4.2 on RHEL AS 4. Thanks! Paul (1 Reply)
Discussion started by: paul99
1 Replies

7. Shell Programming and Scripting

OR operator syntax question in AWK script

Hi guys, I confused about syntax used in OR script as follow: I have this sample file separated by "|" containing: January|Month No. 1 February|Month No. 2 March|Month No. 3 April|Month No. 4 May|Month No. 5 June|Month No. 6 July|Month No. 7 August|Month No. 8 September|Month No. 9... (11 Replies)
Discussion started by: cgkmal
11 Replies

8. Shell Programming and Scripting

Syntax error using Awk

more report2.txt how to modify the AWK to print above out put for given n no of inputs using report2.txt file? out put should be (3 Replies)
Discussion started by: kanakaraju
3 Replies

9. UNIX for Dummies Questions & Answers

syntax error: invalid arithmetic operator

hi, i have a bash script that i want to receive a a string from another bash file. But because the string has a dot in the middle it gives me an error. The error is in this line: let valor=$1 and the value passed is rules.txt the error is: let: valor=rules.txt: syntax error: invalid... (2 Replies)
Discussion started by: limadario
2 Replies

10. Shell Programming and Scripting

awk if else syntax error

Could somebody gently point out the error of my ways in the below (the flu I'm fighting might be contributing to my current haplessness) awk -F="\t" \ '{ for (i = 1; i <= NR; i++); FNR == i; { if (length($3) < 56 && length($1) > 56) $1=($1" "$2); $2=$3; $3=$4; ... (1 Reply)
Discussion started by: Andrew767
1 Replies
EXPR(1) 						      General Commands Manual							   EXPR(1)

NAME
expr - evaluate arguments as an expression SYNOPSIS
expr arg ... DESCRIPTION
The arguments are taken as an expression. After evaluation, the result is written on the standard output. Each token of the expression is a separate argument. The operators and keywords are listed below. The list is in order of increasing precedence, with equal precedence operators grouped. expr | expr yields the first expr if it is neither null nor `0', otherwise yields the second expr. expr & expr yields the first expr if neither expr is null or `0', otherwise yields `0'. expr relop expr where relop is one of < <= = != >= >, yields `1' if the indicated comparison is true, `0' if false. The comparison is numeric if both expr are integers, otherwise lexicographic. expr + expr expr - expr addition or subtraction of the arguments. expr * expr expr / expr expr % expr multiplication, division, or remainder of the arguments. expr : expr The matching operator compares the string first argument with the regular expression second argument; regular expression syntax is the same as that of ed(1). The (...) pattern symbols can be used to select a portion of the first argument. Otherwise, the matching operator yields the number of characters matched (`0' on failure). ( expr ) parentheses for grouping. Examples: To add 1 to the Shell variable a: a=`expr $a + 1` To find the filename part (least significant part) of the pathname stored in variable a, which may or may not contain `/': expr $a : '.*/(.*)' '|' $a Note the quoted Shell metacharacters. SEE ALSO
ed(1), sh(1), test(1) DIAGNOSTICS
Expr returns the following exit codes: 0 if the expression is neither null nor `0', 1 if the expression is null or `0', 2 for invalid expressions. EXPR(1)
All times are GMT -4. The time now is 09:04 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy