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Full Discussion: Getting syntax error with awk ternary operator
Top Forums Shell Programming and Scripting Getting syntax error with awk ternary operator Post 302942144 by Michael Stora on Friday 24th of April 2015 05:15:44 PM
Old 04-24-2015
Not sure what you mean by which syntax error? I posted the entire awk error output, there was nothing else.

OK, so I seperated it out into single expressions:
Code:
hour >= 12? amPm=" PM" : amPm=" AM"
hour >= 12? hour = hour - 12
hour == 0? hour = 12

The first line works, but the second two do not.
Code:
awk: cmd. line:11:                      hour >= 12? hour = hour - 12
awk: cmd. line:11:                                                  ^ unexpected newline or end of
awk: cmd. line:12:                      hour == 0? hour = 12
awk: cmd. line:12:                                          ^ unexpected newline or end of string

Is there some reason it works for strings and not for numbers?

I see your edit while I was posting. I don't think your code example handles midnight correctly, which is the reason I did not try to do it on one conditional.

00:00 needs to become 12:00 AM not 00:00 AM.

I'm just as interested in understanding why it is not working than finding working code.

Mike

---------- Post updated at 02:15 PM ---------- Previous update was at 02:06 PM ----------

Trying something else:
Code:
amPm= hour >= 12? " PM" : " AM"
hour= hour - hour >= 12? 12 : 0
hour= hour == 0? hour = 12 : hour

No errors. I need to ckeck the output.

So if that is the right way to use it, why do the string lines do exactly what is expected of them?
Code:
hour >= 12? amPm=" PM" : amPm=" AM"
$19 == "V"? valid = "0" : valid = $19
$22 == ""? comment = "0" : comment = $22

Mike
Last edited by Michael Stora; 04-24-2015 at 06:21 PM..
 

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rt-email-dashboards(8)					     Request Tracker Reference					    rt-email-dashboards(8)

NAME

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