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Operating Systems Linux SuSE Find command doesn't pipe the output as required. Post 302940241 by Vipin Batra on Thursday 2nd of April 2015 09:41:20 AM
Old 04-02-2015
The execution gets stuck after first echo (which displays the string to be matched from the out file).
When the find command is executed on shell, it indeed returns the results (matching files) but this is not the case when I run via script. So, I concluded that find is the one creating a problem while piping output.
 

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PREG_MATCH(3)								 1							     PREG_MATCH(3)

preg_match - Perform a regular expression match

SYNOPSIS
int preg_match (string $pattern, string $subject, [array &$matches], [int $flags], [int $offset]) DESCRIPTION
Searches $subject for a match to the regular expression given in $pattern. PARAMETERS
o $pattern - The pattern to search for, as a string. o $subject - The input string. o $matches - If $matches is provided, then it is filled with the results of search. $matches[0] will contain the text that matched the full pattern, $matches[1] will have the text that matched the first captured parenthesized subpattern, and so on. o $flags -$flags can be the following flag: o PREG_OFFSET_CAPTURE - If this flag is passed, for every occurring match the appendant string offset will also be returned. Note that this changes the value of $matches into an array where every element is an array consisting of the matched string at offset 0 and its string offset into $subject at offset 1. o $offset - Normally, the search starts from the beginning of the subject string. The optional parameter $offset can be used to specify the alternate place from which to start the search (in bytes). Note Using $offset is not equivalent to passing substr($subject, $offset) to preg_match(3) in place of the subject string, because $pattern can contain assertions such as ^, $ or (?<=x). Compare: <?php $subject = "abcdef"; $pattern = '/^def/'; preg_match($pattern, $subject, $matches, PREG_OFFSET_CAPTURE, 3); print_r($matches); ?> The above example will output: Array ( ) while this example <?php $subject = "abcdef"; $pattern = '/^def/'; preg_match($pattern, substr($subject,3), $matches, PREG_OFFSET_CAPTURE); print_r($matches); ?> will produce Array ( [0] => Array ( [0] => def [1] => 0 ) ) RETURN VALUES
preg_match(3) returns 1 if the $pattern matches given $subject, 0 if it does not, or FALSE if an error occurred. Warning This function may return Boolean FALSE, but may also return a non-Boolean value which evaluates to FALSE. Please read the section on Booleans for more information. Use the === operator for testing the return value of this function. CHANGELOG
+--------+---------------------------------------------------+ |Version | | | | | | | Description | | | | +--------+---------------------------------------------------+ | 5.3.6 | | | | | | | Returns FALSE if $offset is higher than $subject | | | length. | | | | | 5.2.2 | | | | | | | Named subpatterns now accept the syntax | | | (?<name>) and (?'name') as well as (?P<name>). | | | Previous versions accepted only (?P<name>). | | | | +--------+---------------------------------------------------+ EXAMPLES
Example #1 Find the string of text "php" <?php // The "i" after the pattern delimiter indicates a case-insensitive search if (preg_match("/php/i", "PHP is the web scripting language of choice.")) { echo "A match was found."; } else { echo "A match was not found."; } ?> Example #2 Find the word "web" <?php /* The  in the pattern indicates a word boundary, so only the distinct * word "web" is matched, and not a word partial like "webbing" or "cobweb" */ if (preg_match("/web/i", "PHP is the web scripting language of choice.")) { echo "A match was found."; } else { echo "A match was not found."; } if (preg_match("/web/i", "PHP is the website scripting language of choice.")) { echo "A match was found."; } else { echo "A match was not found."; } ?> Example #3 Getting the domain name out of a URL <?php // get host name from URL preg_match('@^(?:http://)?([^/]+)@i', "http://www.php.net/index.html", $matches); $host = $matches[1]; // get last two segments of host name preg_match('/[^.]+.[^.]+$/', $host, $matches); echo "domain name is: {$matches[0]} "; ?> The above example will output: domain name is: php.net Example #4 Using named subpattern <?php $str = 'foobar: 2008'; preg_match('/(?P<name>w+): (?P<digit>d+)/', $str, $matches); /* This also works in PHP 5.2.2 (PCRE 7.0) and later, however * the above form is recommended for backwards compatibility */ // preg_match('/(?<name>w+): (?<digit>d+)/', $str, $matches); print_r($matches); ?> The above example will output: Array ( [0] => foobar: 2008 [name] => foobar [1] => foobar [digit] => 2008 [2] => 2008 ) NOTES
Tip Do not use preg_match(3) if you only want to check if one string is contained in another string. Use strpos(3) or strstr(3) instead as they will be faster. SEE ALSO
PCRE Patterns, preg_quote(3), preg_match_all(3), preg_replace(3), preg_split(3), preg_last_error(3). PHP Documentation Group PREG_MATCH(3)
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