Hello ,
I am trying to replace a word :: complete to Failed .
work: complete
Sed command which i am using is given below ::
sed s/work: complete/Failed/g temp1.txt > temp2.txt (Sed command is grabled if i use the above .. because of space which is there between work: and complete. I... (6 Replies)
Hi,
I have to replace the character AL2 with AL16 which I have in one of my text file .
I used the sed command like this
sed 's/sed 's/AL2/AL16/g' test_carr.dat>test_carr1.dat
But it is not replacing this value to the output file.
The test_carr.dat file contains data like this
cat... (1 Reply)
Hi everybody,
I have come across a typical problem:
I need to use sed command to replace an apostrophe but it is saying no match found in the error
sed -e 's/`/'/g' ...but it is not working. Can you please tell me how to use this apostrophe in this sed command please. Thanks.
Rubin (8 Replies)
Hello,
I want to remove the / found when executing the date command. When I use: date +%D | sed 's/\///'
I get: 1105/09
I tried: date +%D | sed 's/\*$///'
I need to remove all / from the date command, but it does not seem to work (5 Replies)
I need to search for a keyword UTF-16 in a list of files if that keyword is found then i need to convert the file to UTF-8 format using iconv command.
After this i should substitute the UTF-16 keyword inside the file to UTF-8.
Please suggest how to do this in shell scripting. (11 Replies)
I ran one the script in debug mode in linux and have a problem
ret='$prmAttunityUser=ais'
Now i need to remove $ from this '$prmAttunityUser=ais' so i had added a sed command like this sed 's/$//g' but its not working could you all please help me with an alternate command
I want the output... (3 Replies)
Hi All,
I am trying to use a variable within the sed command but I am not able to get the output.
When I am using the following command (without variable) its working fine:
sed -n '/2011\/12\/10 18:11:11./,$p' < Log.txt > Delta_Log.txt
But when I am putting the value 2011\/12\/10... (4 Replies)
I have a file that contains lines like this:
allgroups: cn=Role1,cn=groups,o=xyz,st=mn,c=us
allgroups: cn=Role1,cn=groups,o=xyz,st=mn,c=us
I want to remove the string :
,cn=groups,o=xyz,st=mn,c=us
and so I tried to use SED. i tried to assign it to a variable and use it:
... (3 Replies)
Hi,
I want to use a code like
sed -n "1,9988p" filename | wc -l
I tried
from=1
till=9988
sed -n "/$from/,/$till/p" filename |wc -l
Issue:
sed -n "1,9988p" filename | wc -l -- Returns 9988 rows
But
sed -n "/$from/,/$till/p" filename |wc -l # Returns > 9988 rows(Complete file)
I... (2 Replies)
Hi,
I have a script that replaces one string with the other in all files under the specified directory.
!/bin/bash
# **************** Change Variables Here ************
startdirectory="/opt/app/properties/tmp_new"
searchterm="Oracle/Middleware/"
replaceterm=""
#... (1 Reply)
Discussion started by: mohtashims
1 Replies
LEARN ABOUT PHP
escapeshellarg
ESCAPESHELLARG(3) 1 ESCAPESHELLARG(3)escapeshellarg - Escape a string to be used as a shell argumentSYNOPSIS
string escapeshellarg (string $arg)
DESCRIPTION escapeshellarg(3) adds single quotes around a string and quotes/escapes any existing single quotes allowing you to pass a string directly
to a shell function and having it be treated as a single safe argument. This function should be used to escape individual arguments to
shell functions coming from user input. The shell functions include exec(3), system(3) and the backtick operator.
On Windows, escapeshellarg(3) instead removes percent signs, replaces double quotes with spaces and adds double quotes around the string.
PARAMETERS
o $arg
- The argument that will be escaped.
RETURN VALUES
The escaped string.
EXAMPLES
Example #1
escapeshellarg(3) example
<?php
system('ls '.escapeshellarg($dir));
?>
SEE ALSO escapeshellcmd(3), exec(3), popen(3), system(3), backtick operator.
PHP Documentation Group ESCAPESHELLARG(3)