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Full Discussion: sed command issue in script
Top Forums Shell Programming and Scripting sed command issue in script Post 302937770 by oberoi1403 on Monday 9th of March 2015 09:42:24 AM
Old 03-09-2015
Double quotes

No its not working . I am getting the same error

---------- Post updated at 08:42 AM ---------- Previous update was at 08:24 AM ----------

Quote:
Originally Posted by Franklin52
Use double quotes instead of single quotes to expand the shell variables:
Code:
sed -n "/$FromTime/,/$ToTime/p" $logFile  > new_log.log

I tested that wrong.. sorry.. I am still getting the same error

Last edited by oberoi1403; 03-09-2015 at 10:40 AM..
 

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ESCAPESHELLARG(3)							 1							 ESCAPESHELLARG(3)

escapeshellarg - Escape a string to be used as a shell argument

SYNOPSIS
string escapeshellarg (string $arg) DESCRIPTION
escapeshellarg(3) adds single quotes around a string and quotes/escapes any existing single quotes allowing you to pass a string directly to a shell function and having it be treated as a single safe argument. This function should be used to escape individual arguments to shell functions coming from user input. The shell functions include exec(3), system(3) and the backtick operator. On Windows, escapeshellarg(3) instead removes percent signs, replaces double quotes with spaces and adds double quotes around the string. PARAMETERS
o $arg - The argument that will be escaped. RETURN VALUES
The escaped string. EXAMPLES
Example #1 escapeshellarg(3) example <?php system('ls '.escapeshellarg($dir)); ?> SEE ALSO
escapeshellcmd(3), exec(3), popen(3), system(3), backtick operator. PHP Documentation Group ESCAPESHELLARG(3)
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