Are your first column always the same and in same order?
If yes, this might help extract col2 from all your files , but you need to paste col1 from one of your files.
Should maintain order.
Save this as liuzhencc.awk , give a execute status like chmod 777
hi friends!
i have a script where a execute a veritas command, available_media wich retrieves me a list of tapes .lst
then i execute
cat /tmp/listtapes.lst | grep -v VL |sed '/^$/d'|awk -F, '{print $1, $3, $4, $9}
' > /tmp/media1.lst
but it prints all the columns instead of the four... (3 Replies)
Hello Team,
I have written following command which is giving output is as shown below.
bash-3.00$ grep -i startup catalina.out | tail +2 | sed -n 1p | awk -F" " '{ for (x=1; x<=5; x++) { printf"%s\n", $x } }'
Dec
19,
2010
3:28:39
PM
bash-3.00$
I would like to modify above command to... (2 Replies)
I have a one-line command,
lsusb | awk '{ $1=""; $2=""; $3=""; $4=""; $5=""; $6=""; print $0 }'
It works, and gives the results I expect, I was just wondering if I am missing some easier way to nullify the first 6 column variables?
Something like,
lsusb | awk '{ $(1-6)=""; print $0 }'
But... (10 Replies)
Hi all,
My input file is :
0 13400000 sil
13400000 14400000 a
14400000 14900000 dh
14900000 15300000 a
15300000 16500000 R
16500000 17000000 k
17000000 17300000 u
17300000 17600000 th
17600000 17900000 sil
17900000 18400000 th
18400000 18900000 a
18900000 19600000 g
19600000 19900000... (1 Reply)
Hi,
Can anyone help with the below please?
I have written some code which takes an input file, and and prints the contents out to a new file - it then loops round and prints the same columns, but increments the ID column by 1 each time.
Input file;
NAME,1,15-Dec-15,
NAME,1,21-Dec-15,... (9 Replies)
Hello, I have two tab files with headers
File1: with 4 columns
header1 header2 header3 header4
44 a bb 1
57 c ab 4
64 d d 5
File2: with 26 columns
header1.. header5 header6 header7 ... header 22...header26
id1 44 a bb
id2 57 ... (6 Replies)
Hi everybody,
I have file 1 with 15 columns, I want to change the formatting of the numbers of columns 10,11 and 12 in the scientific notation.
I used the Following script:
awk '{print $10}' file1.dat | awk '{printf "%.2e\n", $1}' > file2.dat
awk '{print $11}' file1.dat | awk '{printf... (7 Replies)
Hi,
I'm trying to copy and paste the sixth column from a bunch of files into a single file having each column pasted in separate columns (and not one after each other in just one column.)
I tried this code but works only partially because it copied and pasted 50 rows of each column... (6 Replies)
Hi All,
i am trying to print required multiple columns dynamically from a fie.
But i am able to print only one column at a time.
i am new to shell script, please help me on this issue.
i am using below script
awk -v COLT=$1 '
NR==1 {
for (i=1; i<=NF; i++) {
... (2 Replies)
Discussion started by: balu1234
2 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)