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Top Forums Shell Programming and Scripting Encrypt and decrypt a password in shell script Post 302936737 by Corona688 on Friday 27th of February 2015 09:54:54 AM
Old 02-27-2015
Quote:
Originally Posted by SekhaReddy
Can anyone suggest me how to decrypt the password from the file and it needs to be connected to the repository as well. And also provide me the sample script file to understand better.

Thanks in advance....
Quote:
While script file is running in informatica it shouldnot prompt.
We get threads asking for this again, and again.

Encryption does not work that way. Period. No ifs, ands, or buts. It just doesn't. You are asking for a logical contradiction -- if the script must output the unencrypted password without user intervention, it by definition contains complete instructions for retrieving the password. This is one big reason why embedding passwords in scripts is a bad habit.

If you want to conceal the password from the user, chmod is the protection you need. Prevent them from reading the script, or put it in another file which they cannot read themselves. Or, arrange a way that doesn't require a password.

Last edited by Corona688; 02-27-2015 at 11:00 AM..
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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