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Top Forums Programming How to replace the complex strings from a file using sed or awk? Post 302936263 by drl on Tuesday 24th of February 2015 08:43:50 AM
Old 02-24-2015
Hi, Badhrish.
Quote:
Could you please let me know where exactly to feed the input files in your code.
The heart of the solution are these lines:
Code:
diff -y --suppress-common-lines data? |
colordiff |
ansifilter -B   # -B bbcode; -H html; -L latex, etc.

the input files are are provided just like you did with with your diff, except that I called them data1 and data2, and I used the shell meta-character "?" to allow expansion of those filenames.

If you are just looking at the output at a terminal, then ansifilter is not required. I used it to produce bbcode markup to paste here. There are other uses, for example if you would be including the output in an HTML email message.
Quote:
... is there a way to get the text coloured exactly in the position where the discrepancy is? Something like below ...
Nothing occurs to me off-hand, but a Google search might be useful. If I get some time, I'll look into it.

Best wishes ... cheers, drl
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
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