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Top Forums Shell Programming and Scripting Count The Number Of Delimiters using awk or better Post 302934086 by BrahmaNaiduA on Wednesday 4th of February 2015 01:48:08 PM
Old 02-04-2015
Count The Number Of Delimiters using awk or better

What to know the way to count the number of delimiters in each record by ignoring the escape delimiters.
Code:
 

Sample Data:
12345678|ABN\|XYZ MED CHEM PTY. LTD.|C||100.00|22|AB"C\|Corp|"XYZ|CDEF"|

I'm using awk -F'|' '{ print NF-1 }' command to find the number of delimiters. this command considering escape character delimiters(\|) also into consideration and returning number of delimiters as 11. 

Excepted Output: 9 

Please help me in this.

 

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PASTE(1)						      General Commands Manual							  PASTE(1)

NAME
paste - paste multiple files together SYNOPSIS
paste [-s] [-d list] file... OPTIONS
-d Set delimiter used to separate columns to list. -s Print files sequentially, file k on line k. EXAMPLES
paste file1 file2 # Print file1 in col 1, file2 in col 2 paste -s f1 f2 # Print f1 on line 1 and f2 on line 2 paste -d : file1 file2 # Print the lines separated by a colon DESCRIPTION
Paste concatenates corresponding lines of the given input files and writes them to standard output. The lines of the different files are separated by the delimiters given with the option -s. If no list is given, a tab is substituted for every linefeed, except the last one. If end-of-file is hit on an input file, subsequent lines are empty. Suppose a set of k files each has one word per line. Then the paste output will have k columns, with the contents of file j in column j. If the -s flag is given, then the first file is on line 1, the second file on line 2, etc. In effect, -s turns the output sideways. If a list of delimiters is given, they are used in turn. The C escape sequences , , \, and are used for linefeed, tab, backslash, and the null string, respectively. PASTE(1)
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