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Full Discussion: Extract directory name
Top Forums Shell Programming and Scripting Extract directory name Post 302933769 by RudiC on Monday 2nd of February 2015 08:18:09 AM
Old 02-02-2015
I don't see the necessity to use a variable if you run an ssh command. From what you showed in post #1, there is an entire directory listing to be processed, and you did not specify the output format desired.

Please provide the entire picture of what you need to do so we can provide a fit soulition.
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SSH-ARGV0(1)						    BSD General Commands Manual 					      SSH-ARGV0(1)

NAME
ssh-argv0 -- replaces the old ssh command-name as hostname handling SYNOPSIS
hostname | user@hostname [-l login_name] [command] hostname | user@hostname [-afgknqstvxACNTX1246] [-b bind_address] [-c cipher_spec] [-e escape_char] [-i identity_file] [-l login_name] [-m mac_spec] [-o option] [-p port] [-F configfile] [-L port:host:hostport] [-R port:host:hostport] [-D port] [command] DESCRIPTION
ssh-argv0 replaces the old ssh command-name as hostname handling. If you link to this script with a hostname then executing the link is equivalent to having executed ssh with that hostname as an argument. All other arguments are passed to ssh and will be processed normally. OPTIONS
See ssh(1). FILES
See ssh(1). AUTHORS
OpenSSH is a derivative of the original and free ssh 1.2.12 release by Tatu Ylonen. Aaron Campbell, Bob Beck, Markus Friedl, Niels Provos, Theo de Raadt and Dug Song removed many bugs, re-added newer features and created OpenSSH. Markus Friedl contributed the support for SSH protocol versions 1.5 and 2.0. Jonathan Amery wrote this ssh-argv0 script and the associated documentation. SEE ALSO
ssh(1) Debian Project September 7, 2001 Debian Project
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