First, never tell us: "i use your command and make this script but it wouldn't work"! Show us the exact output from running the script that explains to us exactly what didn't work. If you don't show us how it isn't working, it makes it a huge guessing game for all of us (especially those of us who are using a different operating system and shell than you're using).

Second, there is a HUGE difference between running a program and feeding its output to awk as RudiC suggested with:

Code:

ls -l | awk ...

and running a program, saving its output in a variable, executing a fixed string, and feeding the results of the command named by that string to awk as your code is doing:

Code:

output=$(ls -l $1) 
"output" | awk ...

Why are you storing the output from ls in a variable.

Third: You have an extraneous single quote before the -F option to awk.

And, fourth: I don't see how this script is going to work if you use ls -l instead of ls without the -l option. (With ls -l output, $1 in awk is never going to match Full nor level.)

Please try running your script more like RudiC suggested:

Code:

ls "$1" | awk -F"_" -v Ystd=$(date +"%Y%m%d" -d"-4 day") '
        $3>Ystd        {if ($1 ~ "full") printf "10"
                         if ($1 ~ "level") printf "5"
                         sub (/^.* /,"")
                         printf "\t%s\n", $0
                        }'