Could you please try following code and let me know if this helps you.
Now when we run the script as follows.
Similar way you can pass your variable to this script.
EDIT: Adding a non oneliner form of same solution.
Thanks,
R. Singh
Last edited by RavinderSingh13; 01-29-2015 at 03:36 AM..
Reason: Added a non one liner form of solution now
Hi,
I have a ksh script which extracts files from a directory in the following format, eg:
10288.Job.rescheduled.1154647335
I need to extract the unix timestamp (eg 1154647335) and convert it to dd-mm-yyyy.
Can anyone suggest anything for this?
thanks. :confused: (6 Replies)
I am currently running the following Korn shell script which works fine:
#!/usr/bin/ksh
count=`db2 -x "select count(*) from schema.tablename"`
echo "count"
I would like to add a "where" clause to the 2nd line that would allow me to get a record count of all the records from schema.tablename... (9 Replies)
Hello:
I have a script that requires the use of DOY (as a variable) instead of YY/MM/DD. I already obtained these parameters from downloaded files and stored them as variables (i.e. $day, $month, $year).
Is there any simple script that I could incorporate in mine to do this job?
Regards,
... (8 Replies)
Hi folks,
I need to write a script that should activate a process according to the current hour.
The process should be activatet only if the hour is between midnight (00:00) and 07:00.
How should I create the condition?
Thanks in advance,
Nir (2 Replies)
I need to use a shell script, using sed command how to replace date variable value in following format.
04/18/2012 11:38:55
Because the sed is treating the '/' as a parameter instead of the value of a variable, and hence there is the message as
sed: command garbled: s/insert/04/18/2012... (9 Replies)
Hi All,
I am trying to add one day to the busdt variable i am extracting from a file (DynamicParam.env). I am deriving the busdt as below.
Is there any function which I can use to derive as below.
If busdt=20120910, then the new derived variable value should be 20120911
If... (2 Replies)
I am not able to pass date stored in a variable as an argument to date command. I get current date value for from_date and to_date
#!/usr/bin/ksh
set -x
for s in server ; do
ssh -T $s <<-EOF
from_date="12-Jan-2015 12:02:09"
to_date="24-Jan-2015 13:02:09"
echo \$from_date
echo... (7 Replies)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Hello All,
we what we call a parameter file (.txt) where my application read dynamic values when the job is triggered, one of such values are below:
abc.txt
------------------
line1
line2
line3
$$EDWS_DATE_INSERT=08-27-2019
line4
$$EDWS_PREV_DATE_INSERT=08-26-2019
I am trying to... (1 Reply)