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Top Forums Programming SQL*PLUS How to display a count of 0 Post 302932374 by cero on Wednesday 21st of January 2015 07:37:28 AM
Old 01-21-2015
You can get a count of 0 by including 'ME' in the data set you select from:
Code:
select owner,table_name,count(table_name)
  from (select owner,table_name from all_tables
        union all
        select 'ME',null table_name from dual)
 where owner = 'ME'
 group by owner,table_name
/

ME                                                                            0

But be careful: count(*) counts the number of records. Because there now is a record with owner='ME' you'd get a result of 1. You get 0 because table_name is null in that record.

Last edited by cero; 01-21-2015 at 08:47 AM..
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PG_COPY_FROM(3) 														   PG_COPY_FROM(3)

pg_copy_from - Insert records into a table from an array

SYNOPSIS
bool pg_copy_from (resource $connection, string $table_name, array $rows, [string $delimiter], [string $null_as]) DESCRIPTION
pg_copy_from(3) inserts records into a table from $rows. It issues a COPY FROM SQL command internally to insert records. PARAMETERS
o $connection - PostgreSQL database connection resource. o $table_name - Name of the table into which to copy the $rows. o $rows - An array of data to be copied into $table_name. Each value in $rows becomes a row in $table_name. Each value in $rows should be a delimited string of the values to insert into each field. Values should be linefeed terminated. o $delimiter - The token that separates values for each field in each element of $rows. Default is TAB. o $null_as - How SQL NULL values are represented in the $rows. Default is N ("\N"). RETURN VALUES
Returns TRUE on success or FALSE on failure. EXAMPLES
Example #1 pg_copy_from(3) example <?php $db = pg_connect("dbname=publisher") or die("Could not connect"); $rows = pg_copy_to($db, $table_name); pg_query($db, "DELETE FROM $table_name"); pg_copy_from($db, $table_name, $rows); ?> SEE ALSO
pg_copy_to(3). PHP Documentation Group PG_COPY_FROM(3)
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