If infilecontains:
the above script will print both lines even though neither one meets the specified criteria. However, if the input never contains more than two fields and both fields always contain at least one character, it will do what is wanted.
I am awk-ing a line, and only want to get the results of the five chrs. following my field seperator. the line of prose is:
Unit=01982 (PICO RIVERA)
Unit=I1001 (INTERMOUNTAIN AREA)
Unit=E1000 (INTERMOUNTAIN WEST DIVISION)
failing in using an awk of:
awk -F= '/Unit/{print $2 length(5)}'... (3 Replies)
Hi!
How can I print out a specific range of rows, like "cat file | awk NR==5,NR==9", but in the END-statement?
I have a small awk-script that finds specific rows in a file and saves the line number in an array, like this:
awk '
BEGIN { count=0}
/ZZZZ/ {
list=NR
... (10 Replies)
Hi,
I want to echo the 15th line from a file named as abc.txt, also i want to echo only the values in that line not the line number.
Thanks in advance:) (4 Replies)
hi all
I would like to help me find the problem with this script to find and print to the screen a specific date of a log file that I have on my server, the date it is received as the first argument in the script $ 1
Here I show you a few lines that made the idea of my log file:
****... (4 Replies)
Hi,
I am in a situation to print the message on a column, where the each line starting position should be same.
For example code:
HOSTNAME1="1.2.3.4.5.6.7"
TARGET_DIR="/tmp"
echo "HOSTNAME1:" "$HOSTNAME1" | awk -v var="Everyone" '{len=55-length;printf("%s%*s\n",$0,len,var)}'
echo... (4 Replies)
Hello,
i need help with awk.
I have this file:
cat number
DirB port 67 er_enc_out 0 er_bad_os 0
DirB port 71 er_enc_out 56 er_bad_os 0
DirB port 74 er_enc_out 0 er_bad_os 0
DirB port 75 ... (4 Replies)
I want to print specific range of rows and then its columns using awk command.
lets say if a file contain 15 line then i need to print line 5 to 9.
awk '{print;for( NR>=5&&NR<=9); do; print "<tr>\n<td>"$1"</td><td>"$2"</td><td>"$3"</td>\n</tr" done}' xyz.csv
not sure what's wrong... (9 Replies)
In the below awk I am trying to print expName only if another tag planExecuted is true. In addition to the expName I am also printing planShortID. For some reason the word experiment gets printed so I remove it with sed. I have attached the complete index.html as well as included a sample of it... (1 Reply)
Discussion started by: cmccabe
1 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)