That depends on what your system - which you fail to mention - provides. Above is an example of GNU date, which is not avaiable on every system. (Free)BSD provides
Recent bash has the printf "%(datefmt)T" builtin, but that needs epoch seconds, which may be difficult to get at.
Hi,
I would like to find out how can i calculate a date which is 3 months ago. I intend to run a cron job on the 1st of every month, and calculate the month 4 months earlier from the date. For example, if today's date is 1st May 2007, i would like to return 012007( January 2007).
i can get... (1 Reply)
I want to calculate the date of next satureday of current date using shell script.
Suppose, today is 27-feb-08
I want to get the date of next satureday, which means 01-mar-08, in the formate '' YYMMDD ".
I do this in ksh..
Please tell me any type of command which help me out.
Thanks in... (3 Replies)
Hi guys,
I had a scenario...
1. I had to get the previous days date in yyyymmdd format
2. i had to create a file with Date inthe format yyyymmdd.txt format
both are different
thanks guys in advance.. (4 Replies)
Hello
I would like to help me create a script that:
Given a date, more precisely a year, one month and one day. must calculate the day after
-Input: Year, Month, Day
-Output: Next day the Year-Month-Day
thanks (9 Replies)
I am unable to get this KSH script to work. Can someone help. I've been told this should work with KSH93. Which I think I have on Solaris 10.
If I do a grep -i version /usr/dt/bin/dtksh I get
@(#)Version M-12/28/93d
@(#)Version 12/28/93
@(#)Version M-12/28/93
This is correct for... (5 Replies)
I need to get the next day's date of the user entered date
for example:
Enter date (yyyy/mm/yy):
2013/10/08I need to get the next day's date of the user entered date
Desired Output:
2013/10/09Though there are ways to achieve this is Linux or Unix environment (date command) ,I need to... (1 Reply)
How to get Julian date (Three digit) of a given date (Not current date)? I do not have root privilege - so can not use date -d. Assume that we have three variables year, month and date.
Thx (5 Replies)
I Have text like
XXX_20190908.csv.gz need to replace Only date in this format with current date every day
Thanks! (1 Reply)
Discussion started by: yamasani1991
1 Replies
LEARN ABOUT PHP
datetime.settime
DATETIME.SETTIME(3) 1 DATETIME.SETTIME(3)DateTime::setTime - Sets the time
Object oriented style
SYNOPSIS
public DateTime DateTime::setTime (int $hour, int $minute, [int $second])
DESCRIPTION
Procedural style
DateTime date_time_set (DateTime $object, int $hour, int $minute, [int $second])
Resets the current time of the DateTime object to a different time.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $hour
- Hour of the time.
o $minute
- Minute of the time.
o $second
- Second of the time.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.setTime(3) example
Object oriented style
<?php
$date = new DateTime('2001-01-01');
$date->setTime(14, 55);
echo $date->format('Y-m-d H:i:s') . "
";
$date->setTime(14, 55, 24);
echo $date->format('Y-m-d H:i:s') . "
";
?>
Procedural style
<?php
$date = date_create('2001-01-01');
date_time_set($date, 14, 55);
echo date_format($date, 'Y-m-d H:i:s') . "
";
date_time_set($date, 14, 55, 24);
echo date_format($date, 'Y-m-d H:i:s') . "
";
?>
The above examples will output something similar to:
2001-01-01 14:55:00
2001-01-01 14:55:24
Example #2
Values exceeding ranges are added to their parent values
<?php
$date = new DateTime('2001-01-01');
$date->setTime(14, 55, 24);
echo $date->format('Y-m-d H:i:s') . "
";
$date->setTime(14, 55, 65);
echo $date->format('Y-m-d H:i:s') . "
";
$date->setTime(14, 65, 24);
echo $date->format('Y-m-d H:i:s') . "
";
$date->setTime(25, 55, 24);
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2001-01-01 14:55:24
2001-01-01 14:56:05
2001-01-01 15:05:24
2001-01-02 01:55:24
SEE ALSO DateTime.setDate(3), DateTime.setISODate(3).
PHP Documentation Group DATETIME.SETTIME(3)