I need your help, because i know a local variable in a function for example k, it is different of other variable(with the same name k) this a global variable. Is that right?
Code:
dgawk> run
Starting program:
3238860128818202
3 4 7 11 12 13 17 22 23 32 35 37 41 48 49 55 63
Stopping in Rule ...
Breakpoint 1, main() at `deco-int.awk':16
16 parseo_datos();
dgawk> s
parseo_datos() at `deco-int.awk':88
88 k = 1;
dgawk> s
89 inicio = 69;
dgawk> s
90 while (k <= 15) {
dgawk> set k=10
k = 10
dgawk> set inicio=177
inicio = 177
dgawk> p k
k = 10
dgawk> p inicio
inicio = 177
dgawk> s
91 i = campo_enc[k];
dgawk> s
92 data=0;
dgawk> p i
i = "32"
dgawk> s
93 long_data=0;
dgawk> s
94 if (C[i,4] == "F") {
dgawk> s
99 if (C[i,4] == "V") {
dgawk> s
100 long_data = strtonum(quita_ceros(cadhex_to_caddec(substr($0, inicio, C[i,5] * 2))));
dgawk> p C[32,4]
C["324"] = "V"
dgawk> p k
k = 10
dgawk> s
100 long_data = strtonum(quita_ceros(cadhex_to_caddec(substr($0, inicio, C[i,5] * 2))));
dgawk> p k
k = 10
dgawk> n
101 if (long_data <= C[i,6]) {
dgawk> p k
k = 1
the function "quita_ceros", I have it in include file:
Code:
function quita_ceros(cad)
{
k=1;
while (k <= length(cad)) {
if (substr(cad , k , 1) == "0") {
cad = substr(cad, k + 1, length(cad));
continue;
}
else
break;
k++;
}
return cad;
}
if you see the debug, the value of variable global change after call the function "quita_ceros", why? both variable have the same name, but a is local variable and other is a variable global.
Thanks for advance.
Last edited by Scrutinizer; 12-29-2014 at 12:10 AM..
Reason: icode tags => code tags
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Perl::Critic::Policy::BuiltinFunctions::ProhibitLvalueSuUser(Contributed Perl DocumPerl::Critic::Policy::BuiltinFunctions::ProhibitLvalueSubstr(3)NAME
Perl::Critic::Policy::BuiltinFunctions::ProhibitLvalueSubstr - Use 4-argument "substr" instead of writing "substr($foo, 2, 6) = $bar".
AFFILIATION
This Policy is part of the core Perl::Critic distribution.
DESCRIPTION
Conway discourages the use of "substr()" as an lvalue, instead recommending that the 4-argument version of "substr()" be used instead.
substr($something, 1, 2) = $newvalue; # not ok
substr($something, 1, 2, $newvalue); # ok
The four-argument form of "substr()" was introduced in Perl 5.005. This policy does not report violations on code which explicitly
specifies an earlier version of Perl (e.g. "use 5.004;").
CONFIGURATION
This Policy is not configurable except for the standard options.
SEE ALSO
"substr" in perlfunc (or "perldoc -f substr").
"4th argument to substr" in perl5005delta
AUTHOR
Graham TerMarsch <graham@howlingfrog.com>
COPYRIGHT
Copyright (c) 2005-2011 Graham TerMarsch. All rights reserved.
This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
perl v5.16.3 2014-06-09 Perl::Critic::Policy::BuiltinFunctions::ProhibitLvalueSubstr(3)
12-28-2014
