Sponsored Content
Full Discussion: Date format conversion
Top Forums Shell Programming and Scripting Date format conversion Post 302928477 by RavinderSingh13 on Friday 12th of December 2014 04:03:43 AM
Old 12-12-2014
Hello JSKOBS,

Not sure if you have tried command which I have given in post#2, it will give following output as per your requirement.
Kindly let me know if you have tried that command and it doesn't meet your requirement.
Code:
ls -ltr --time-style="long-iso"
-rw-r--r-- 1 singh4     singh4       33 2014-12-12 03:59 test1
drwxrwxr-x 2 singh4     singh4  240 2014-12-12 03:59 test2
drwxr-xr-x 2 singh4     singh4  160 2014-12-12 03:59 test3

Thanks,
R. Singh
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Date format conversion function

Hello, does somebody knows about a function that would convert a date like: YYMMDD into a date like YYYY-MM-DD ? Thank you for your ideas :) (9 Replies)
Discussion started by: Cecile
9 Replies

2. Shell Programming and Scripting

convert date format to mysql date format in log file

I have a comma delimited log file which has the date as MM/DD/YY in the 2nd column, and HH:MM:SS in the 3rd column. I need to change the date format to YYYY-MM-DD and merge it with the the time HH:MM:SS. How will I got about this? Sample input 02/27/09,23:52:31 02/27/09,23:52:52... (3 Replies)
Discussion started by: hazno
3 Replies

3. UNIX for Dummies Questions & Answers

date format conversion

hi, i have a file in which i get date format as 22/APR/2010... now i want the date format to be in 22-04-2010 if the month changes to may the file should also have 05 as month.... pls help (3 Replies)
Discussion started by: siva_nagarajan
3 Replies

4. Shell Programming and Scripting

Date conversion from Standard/given format to seconds/epoch

I am trying get time difference of two dates in secs. Initially I want to convert a standard date format to epoch for two dates and then subtract the two epoch dates. Example : date -d "2007-09-01 17:30:40" '+%s' But this gives me below error date: illegal option -- d Usage: date OS: AIX... (6 Replies)
Discussion started by: bpaac
6 Replies

5. Shell Programming and Scripting

Date format conversion

Hi All, Can someone please let me know how can i convert the date format in unix as follow: From: 24 Oct 2011 i.e $(date +'%d %b %Y') To: 111024 i.e $(date +%y%m%d) Thanks in advance (3 Replies)
Discussion started by: davidtd
3 Replies

6. Shell Programming and Scripting

Military type format date/time conversion

Hello All, I have a requirement to convert a 12 hour format to 24 hour time format and the sample input /out put is below Input Time format : Nov 2 2011 12:16AM Out Put Format : Nov 2 2011 0:16 Input : Nov 2 2011 4:16PM Out Put: Nov 2 2011 16:16 I have done this using a... (6 Replies)
Discussion started by: jambesh
6 Replies

7. Shell Programming and Scripting

Date conversion from 24 hr format to 12 hr format

hi i want to convert date procured from sone operation which will be in 24hr format to 12 hr format displaying AM and PM # date -d @1362545068 Tue Mar 5 23:44:28 EST 2013 # this Tue Mar 5 23:44:28 EST 2013 i want to convert it so that output is as below Tue... (2 Replies)
Discussion started by: vivek d r
2 Replies

8. Shell Programming and Scripting

Date conversion and Format

Hello , I have a record in below format Hostname | Query: 0 | Release: 0 | files: 2 | Files_examined: 2 | SET timestamp=1396778638; | select * from test I need output in below format Hostname | 0 | 0 | 2 | 2 | 04/06/2014|03:03:58 | select * from test I was able to get above output... (1 Reply)
Discussion started by: Tomlight
1 Replies

9. Shell Programming and Scripting

Bash Scripting with date format conversion

I have a script below and wanted to change the output into three different file format (3 separate script) #!bin/bash #input file format postwrf_d01_20131206_0600_f08400.grb2 #postwrf_d01_YYYYMMDD_ZZZZ_f0HHHH.grb2 #zzzz= 0000,0600,1200,1800 (in UTC) #HHHH=00000,00600,01200,01800 ..ect (in... (1 Reply)
Discussion started by: cumulus_255
1 Replies

10. UNIX for Beginners Questions & Answers

Date format conversion how to change this from using nawk to awk

Hi, I have a file where I need to change the date format on the nth field from DD-MM-YYYY to YYYY-MM-DD so I can accurately sort the record by dates From regex - Use sed or awk to fix date format - Stack Overflow, I found an example using nawk. Test run as below: $: cat xyz.txt A ... (2 Replies)
Discussion started by: newbie_01
2 Replies
bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
All times are GMT -4. The time now is 04:43 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy