12-03-2014
Need help with bash shell script
I need to create digit day script that takes a single numeric argument and then it should print out the day of the week using the number modulo 7 formula e.g: 0 - Sunday 6- Saturday 131 - Friday
I am fairly new to unix so I don't know how to use the number modulo 7 formula.
Does the script need if statements?
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LEARN ABOUT DEBIAN
algorithm::checkdigits::mbase_002
CheckDigits::MBase_002(3pm) User Contributed Perl Documentation CheckDigits::MBase_002(3pm)
NAME
CheckDigits::MBase_002 - compute check digits for blood bags (DE), BZUe (DE), VAT Registration Number (DE)
SYNOPSIS
use Algorithm::CheckDigits;
$bb = CheckDigits('blutbeutel');
if ($bb->is_valid('2761011234567893')) {
# do something
}
$cn = $bb->complete('276101123456789');
# $cn = '2761011234567893'
$cd = $bb->checkdigit('2761011234567893');
# $cd = '3'
$bn = $bb->basenumber('2761011234567893');
# $bn = '276101123456789';
DESCRIPTION
ALGORITHM
1. Start with values P = 10, S = 0.
2. Beginning left you do the following for all digits
1. S = (P + digit) modulo 10
2. If S is 0 then S = 10.
3. P = (2 * S) modulo 11
3. The check digit is (11 - P) modulo 10.
METHODS
is_valid($number)
Returns true only if $number consists solely of numbers and the last digit is a valid check digit according to the algorithm given
above.
Returns false otherwise,
complete($number)
The check digit for $number is computed and concatenated to the end of $number.
Returns the complete number with check digit or '' if $number does not consist solely of digits and spaces.
basenumber($number)
Returns the basenumber of $number if $number has a valid check digit.
Return '' otherwise.
checkdigit($number)
Returns the checkdigit of $number if $number has a valid check digit.
Return '' otherwise.
EXPORT
None by default.
AUTHOR
Mathias Weidner, <mathias@weidner.in-bad-schmiedeberg.de>
SEE ALSO
perl, CheckDigits, www.pruefziffernberechnung.de, www.eurocode.org.
perl v5.10.0 2008-05-17 CheckDigits::MBase_002(3pm)