Hi Guys,
I'm tying to split a line similar to this:YO6-2000-30.htm: (3 properties found).......into separate columns, so effectively I need to check for a -, ., :, a tab and a space in the statement.
Any help would be appreciated
Thanks! (7 Replies)
I need help counting the fields and field separators using Nawk.
I have a file that has multiple lines on it and I need to read the file 1 at a time and then count the fields and field separators and then store those numbers in variables. I then need to delete the first 5 fields and the blank... (3 Replies)
I saw a couple of posts here referencing how to handle more than one input field separator in awk. I figured I would share how I (just!) figured out how to turn this line in a logfile:
90000000000000000000010001 name... (4 Replies)
How do I deal with extracting a portion of a record when multiple field separators are involved.
Let's say I have:
Mike Harrington;(555) 555-5555:250:100:175
Christian Dobbins;(555) 555-2358:155:90:201
Susan Dalsass;(555) 555-6279:250:60:50
Archie McNichol;(555) 555-1348:250:100:175
Jody... (3 Replies)
I need to print the second field of a file, taking spaces, tab and = as field separators.
; for 16-bit app support
MAPI=1
CMC=1
CMCDLLNAME32=mapi32.dll
CMCDLLNAME=mapi.dll
MAPIX=1
MAPIXVER=1.0.0.1
OLEMessaging=1
asf=MPEGVideo
asx=MPEGVideo
ivf=MPEGVideo
m3u=MPEGVideo (2 Replies)
Hi,
I am trying to execute this line
awk -F ";" -v OFS=";" '{gsub(/\./,",",$6); print}' FILE
but for multiple fields $6 $7 $8
Do you have a suggstion?
Tried:
awk -F ";" -v OFS="";"" "function GSUB( F ) {gsub(/\./,\",\",$F); print} { GSUB( 6 ); GSUB( 7 ); GSUB( 8 ) } 1"... (2 Replies)
How do I use multiple field separators in awk?
I know that if I use awk -F"", both a and b will be field separators. But what if I need two field separators that both are longer than one letter?
If I want the field separators to be "ab" and "cd", I will not be able to use awk -F"". The ... (2 Replies)
Hello, I have the following input file:
1 3 3 2
3 3 4 0
4 0 5 4
5 2 2 0
5 3 4 0
6 0 3 2
I am trying to remove all zeroes in fields 2 and 4 and replace them with "1's"
I tried the following, but it's not working
awk -F"\t" '{ if (($2==0) || ($4==0) $2=1; $4=1; print $0 ) }' input
... (8 Replies)
so its common knowledge one can print multiple fields with simple commands like this:
echo 12 44 45 552 24 | awk '{print $1,$4,$3}'
but suppose i want to avoid specifying the "$" symbol. is that possible? can something like this be done:
echo 12 44 45 552 24 | awk '{print $(1,4,3)}'
... (9 Replies)
Discussion started by: SkySmart
9 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)