Hi Guys,
I'm tying to split a line similar to this:YO6-2000-30.htm: (3 properties found).......into separate columns, so effectively I need to check for a -, ., :, a tab and a space in the statement.
Any help would be appreciated
Thanks! (7 Replies)
I need help counting the fields and field separators using Nawk.
I have a file that has multiple lines on it and I need to read the file 1 at a time and then count the fields and field separators and then store those numbers in variables. I then need to delete the first 5 fields and the blank... (3 Replies)
I saw a couple of posts here referencing how to handle more than one input field separator in awk. I figured I would share how I (just!) figured out how to turn this line in a logfile:
90000000000000000000010001 name... (4 Replies)
How do I deal with extracting a portion of a record when multiple field separators are involved.
Let's say I have:
Mike Harrington;(555) 555-5555:250:100:175
Christian Dobbins;(555) 555-2358:155:90:201
Susan Dalsass;(555) 555-6279:250:60:50
Archie McNichol;(555) 555-1348:250:100:175
Jody... (3 Replies)
I need to print the second field of a file, taking spaces, tab and = as field separators.
; for 16-bit app support
MAPI=1
CMC=1
CMCDLLNAME32=mapi32.dll
CMCDLLNAME=mapi.dll
MAPIX=1
MAPIXVER=1.0.0.1
OLEMessaging=1
asf=MPEGVideo
asx=MPEGVideo
ivf=MPEGVideo
m3u=MPEGVideo (2 Replies)
Hi,
I am trying to execute this line
awk -F ";" -v OFS=";" '{gsub(/\./,",",$6); print}' FILE
but for multiple fields $6 $7 $8
Do you have a suggstion?
Tried:
awk -F ";" -v OFS="";"" "function GSUB( F ) {gsub(/\./,\",\",$F); print} { GSUB( 6 ); GSUB( 7 ); GSUB( 8 ) } 1"... (2 Replies)
How do I use multiple field separators in awk?
I know that if I use awk -F"", both a and b will be field separators. But what if I need two field separators that both are longer than one letter?
If I want the field separators to be "ab" and "cd", I will not be able to use awk -F"". The ... (2 Replies)
Hello, I have the following input file:
1 3 3 2
3 3 4 0
4 0 5 4
5 2 2 0
5 3 4 0
6 0 3 2
I am trying to remove all zeroes in fields 2 and 4 and replace them with "1's"
I tried the following, but it's not working
awk -F"\t" '{ if (($2==0) || ($4==0) $2=1; $4=1; print $0 ) }' input
... (8 Replies)
so its common knowledge one can print multiple fields with simple commands like this:
echo 12 44 45 552 24 | awk '{print $1,$4,$3}'
but suppose i want to avoid specifying the "$" symbol. is that possible? can something like this be done:
echo 12 44 45 552 24 | awk '{print $(1,4,3)}'
... (9 Replies)
Discussion started by: SkySmart
9 Replies
LEARN ABOUT V7
join
JOIN(1) General Commands Manual JOIN(1)NAME
join - relational database operator
SYNOPSIS
join [ options ] file1 file2
DESCRIPTION
Join forms, on the standard output, a join of the two relations specified by the lines of file1 and file2. If file1 is `-', the standard
input is used.
File1 and file2 must be sorted in increasing ASCII collating sequence on the fields on which they are to be joined, normally the first in
each line.
There is one line in the output for each pair of lines in file1 and file2 that have identical join fields. The output line normally con-
sists of the common field, then the rest of the line from file1, then the rest of the line from file2.
Fields are normally separated by blank, tab or newline. In this case, multiple separators count as one, and leading separators are dis-
carded.
These options are recognized:
-an In addition to the normal output, produce a line for each unpairable line in file n, where n is 1 or 2.
-e s Replace empty output fields by string s.
-jn m Join on the mth field of file n. If n is missing, use the mth field in each file.
-o list
Each output line comprises the fields specifed in list, each element of which has the form n.m, where n is a file number and m is a
field number.
-tc Use character c as a separator (tab character). Every appearance of c in a line is significant.
SEE ALSO sort(1), comm(1), awk(1)BUGS
With default field separation, the collating sequence is that of sort -b; with -t, the sequence is that of a plain sort.
The conventions of join, sort, comm, uniq, look and awk(1) are wildly incongruous.
JOIN(1)