Hi Guys,
I'm tying to split a line similar to this:YO6-2000-30.htm: (3 properties found).......into separate columns, so effectively I need to check for a -, ., :, a tab and a space in the statement.
Any help would be appreciated
Thanks! (7 Replies)
I need help counting the fields and field separators using Nawk.
I have a file that has multiple lines on it and I need to read the file 1 at a time and then count the fields and field separators and then store those numbers in variables. I then need to delete the first 5 fields and the blank... (3 Replies)
I saw a couple of posts here referencing how to handle more than one input field separator in awk. I figured I would share how I (just!) figured out how to turn this line in a logfile:
90000000000000000000010001 name... (4 Replies)
How do I deal with extracting a portion of a record when multiple field separators are involved.
Let's say I have:
Mike Harrington;(555) 555-5555:250:100:175
Christian Dobbins;(555) 555-2358:155:90:201
Susan Dalsass;(555) 555-6279:250:60:50
Archie McNichol;(555) 555-1348:250:100:175
Jody... (3 Replies)
I need to print the second field of a file, taking spaces, tab and = as field separators.
; for 16-bit app support
MAPI=1
CMC=1
CMCDLLNAME32=mapi32.dll
CMCDLLNAME=mapi.dll
MAPIX=1
MAPIXVER=1.0.0.1
OLEMessaging=1
asf=MPEGVideo
asx=MPEGVideo
ivf=MPEGVideo
m3u=MPEGVideo (2 Replies)
Hi,
I am trying to execute this line
awk -F ";" -v OFS=";" '{gsub(/\./,",",$6); print}' FILE
but for multiple fields $6 $7 $8
Do you have a suggstion?
Tried:
awk -F ";" -v OFS="";"" "function GSUB( F ) {gsub(/\./,\",\",$F); print} { GSUB( 6 ); GSUB( 7 ); GSUB( 8 ) } 1"... (2 Replies)
How do I use multiple field separators in awk?
I know that if I use awk -F"", both a and b will be field separators. But what if I need two field separators that both are longer than one letter?
If I want the field separators to be "ab" and "cd", I will not be able to use awk -F"". The ... (2 Replies)
Hello, I have the following input file:
1 3 3 2
3 3 4 0
4 0 5 4
5 2 2 0
5 3 4 0
6 0 3 2
I am trying to remove all zeroes in fields 2 and 4 and replace them with "1's"
I tried the following, but it's not working
awk -F"\t" '{ if (($2==0) || ($4==0) $2=1; $4=1; print $0 ) }' input
... (8 Replies)
so its common knowledge one can print multiple fields with simple commands like this:
echo 12 44 45 552 24 | awk '{print $1,$4,$3}'
but suppose i want to avoid specifying the "$" symbol. is that possible? can something like this be done:
echo 12 44 45 552 24 | awk '{print $(1,4,3)}'
... (9 Replies)
Discussion started by: SkySmart
9 Replies
LEARN ABOUT MOJAVE
dsenableroot
dsenableroot(8) BSD System Manager's Manual dsenableroot(8)NAME
dsenableroot -- enables or disables the root account.
SYNOPSIS
dsenableroot [-d] [-u username] [-p password] [-r rootPassword]
DESCRIPTION
dsenableroot sets the password for the root account if enabling the root user account. Otherwise, if disable [-d] is chosen, the root
account passwords are removed and the root user is disabled.
A list of flags and their descriptions:
-u username
Username of a user that has administrative privileges on this computer.
-p password
Password to use in conjunction with the specified username. If this is not specified, you will be prompted for entry.
-r rootPassword
Password to be used for the root account. If this is not specified for enabling, you will be prompted for entry.
EXAMPLES -dsenableroot
Your username will be used and you will be queried for both your password and the new root password to be set to enable the root
account.
-dsenableroot -d
Your username will be used and you will be queried for only your password to disable the root account.
-dsenableroot -u username -p userpassword -r rootpassword
The supplied arguments will be used to enable the root account.
-dsenableroot -d -u username -p userpassword
The supplied arguments will be used to disable the root account.
Mac OS August 08 2003 Mac OS