@rbatte1
Seems perfect, I'll try it later on.
Update you on the results later on.
Many thanks!
---------- Post updated 07-11-14 at 11:46 AM ---------- Previous update was 06-11-14 at 05:51 PM ----------
@rbatte1
It works! After some slight changes (in bold) because of my files names
Code:
find ./path/ -type f | sed -e 's/_R.*$//' -e 's/_R//'|sort -u | while read path_file # Or however you generate your file list
do
file="${path_file##*/}" # Get just the file bit, dropping the path
echo "command -1 ${path_file}_R1_val_1.fq.gz -2 ${path_file}_R2_val_2.fq.gz --un-conc-gz $file --several --others --parameters"
done
@gandolf989
Thanks for the suggestion, actually the command is already a perl wrapper.
That is away ahead for my state of knowledge, hope to get there some day...
This User Gave Thanks to sargotrons For This Post:
My program usage takes the form for example;
$ theApp 2 "one or more words"
i.e. 3 command line arguments; application name, an integer, some text
My code includes the following 4 lines:
int anInteger;
char words;
sscanf(argv, "%d", &anInteger);
sscanf(argv, "%s", &message);
Based... (2 Replies)
I am trying to print command line arguments one per second. I have this
while
do
echo "6"
shift
echo "5"
shift
echo "4"
shift
echo "3"
shift
echo "2"
shift
echo "1"
shift
done (2 Replies)
I have this while loop and at the end I am trying to get it to tell me the last argument I entered. And with it like this all I get is the sentence with no value for $1. Now I tried moving done after the sentence and it printed the value of $1 after every number. I don't want that I just want... (2 Replies)
Hi,
I have to store all the command line arguments into an array.
I have the following code.
**********************
#! /bin/sh
set -A arr_no_updates
i=1
while
do
arr_no_updates=$($i)
echo ${arr_no_updates}
i=$(($i+1))
done**************** (1 Reply)
I have this code, I thought it would automatically know the args sent to script when called from shell. But it seems to not see any...
main script:
. args
. errors
. opt
. clean
dbfile=""
opfile=""
# calls function in script below
chkarg
#check commands (2 Replies)
Hi,
i have a perl script named test.pl. It is executed as
cat *.log|test.pl
i need the complete command line args. I tried using basename $0 but im getting test.pl only but not cat *.log...
Can anyone help me on this.
Thanks in advance (3 Replies)
Hi,
Can you please hint me how to achieve the below?
Input:
$./script.sh start 1 2
Internally inside the script i want to set a single variable with $2 and $3 value?
Output:
CMD=$1
ARGS=$2 $3
--VInodh (10 Replies)
Store args passed in array but not the first 2 args.
# bash
declare -a arr=("$@")
s=$(IFS=, eval 'echo "${arr}"')
echo "$s"
output:
sh array.sh 1 2 3 4 5 6
1,2,3,4,5,6
Desired output:
sh array.sh 1 2 3 4 5 6
3,4,5,6 (2 Replies)
11-07-2014
