Sponsored Content
Top Forums Shell Programming and Scripting How to pass position parameter into function.? Post 302922550 by ken6503 on Sunday 26th of October 2014 11:39:42 AM
Old 10-26-2014
How to pass position parameter into function.?

Hi Gurus,

I have request which needs to pass position parameter to a function. I tried below simple code, it doesn't work.

Code:
#!/bin/bash
func_1(){
echo $1
}

func_1
$ ./set_file abc

$

do I need add some to get the position para first?

thanks in advance.
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Position independent Parameter passing

Hi all, When parameters are passed to the shell script, they are dereferenced by their position. For example, I call myTest.sh and pass two parameters param1 and param2 as following: ./myTest.sh param1 param2 In the script, myTest.sh, I refer to first parameter (param1 ) as $1 and second... (1 Reply)
Discussion started by: sonaluphale
1 Replies

2. Shell Programming and Scripting

How to pass a parameter

Hi all, How to pass a parameter from a oracle pl/sql procedure parameter to shell environment and use it? (1 Reply)
Discussion started by: megh
1 Replies

3. Shell Programming and Scripting

pass parameter to function

HI all I have a code like ############################################## minyear() { curryear=$1 echo $curryear } ##Main Program ## minyear exit ####### when i execute "sh scriptname 2005" output should be like 2005 but the output is blank. I guess i need to pass parameter to... (3 Replies)
Discussion started by: vasuarjula
3 Replies

4. Shell Programming and Scripting

What is the maximum number of parameter we can pass to a shell script function?

what is the maximum number of parameter we can pass to a shell script function (8 Replies)
Discussion started by: alokjyotibal
8 Replies

5. Shell Programming and Scripting

How to pass parameter to User defined function in shell script?

Hello, Can anyone guide me tin passing parameters into user defined function of shell script (KSH). Here is my code, InsertRecord() { DB_TBL=$(sqlplus $USERID/$PASSWORD@$DATABASE << EOF set head off set feed off set serveroutput on INSERT INTO TBL1 ( OLD_VAL, NEW_VAL, ... (7 Replies)
Discussion started by: Poonamol
7 Replies

6. Shell Programming and Scripting

Pass command as a function parameter

Hi guys, can someome help with this question, I have defined a function that takes a command as a parameter, but when the command is executed from the function it will throw errors because what I believe is a special character escaping issue. I tried using the backslash to escape the pipe | and >... (2 Replies)
Discussion started by: marouanix
2 Replies

7. Shell Programming and Scripting

How to pass a function with a variable parameter into another variable?

Hello again :) Am currently trying to write a function which will delete a record from a file. The code currently looks as such: function deleteRecord() { clear read -p "Please enter the ID of the record you wish to remove: " strID ... (2 Replies)
Discussion started by: U_C_Dispatj
2 Replies

8. Shell Programming and Scripting

How to use this position parameter?

Hi Gurus, I want split one huge line file to multiple line, I got code from you guys yesterday. I want put the code in a script which use two position parameter when run the script. my code like: awk '{for (i=1; i<=length($0); i+=$2) print substr($0, i, $2)}' $1 > $1_split when I run the... (6 Replies)
Discussion started by: ken6503
6 Replies

9. Shell Programming and Scripting

How to pass function parameter to do loop?

Hi All, I have created one function for KSH and was running well with one parameter input since I just had to use $1 to get the parameter. Now I want to do loop for each parameter(actually filenames) . I have try to use do loop, but $i does not resolve to parameter instead it resolves to 1,... (5 Replies)
Discussion started by: mysocks
5 Replies

10. Homework & Coursework Questions

How to Dynamically Pass Parameter to plsql Function & Capture its Output Value in a Shell Variable?

Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted! 1. The problem statement, all variables and given/known data: 2. Relevant commands, code, scripts, algorithms: #! /bin/ksh v="ORG_ID" ... (2 Replies)
Discussion started by: sujitdas2104
2 Replies
bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
All times are GMT -4. The time now is 08:18 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy