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Full Discussion: Date minus 1 day
Top Forums Shell Programming and Scripting Date minus 1 day Post 302922103 by Samuel12 on Wednesday 22nd of October 2014 11:41:34 AM
Old 10-22-2014
Date minus 1 day

Hi the below code is failing i am trying to generate do the following:

2014-10-22 11:26:00 (Substract 24 hrs)
should produce
2014-10-21 11:26:00

I need the same formatting below because that gets inputted into code for an applcication report and it must match the applicaiton accepted format.

Code:
hourt="$d $h:$m:00"
hour2="$d $(printf '%02d:%02d:00' $((${h#0} - 12)) $m)"


2014-10-22 11:38:00
2014-10-22 -13:38:00


How do i subtract 1 day? without the negative being produced.



Thanks,

Sam
 

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get_midi_length(3alleg4)					  Allegro manual					  get_midi_length(3alleg4)

NAME
get_midi_length - Determines the total playing time of a midi, in seconds. Allegro game programming library. SYNOPSIS
#include <allegro.h> int get_midi_length(MIDI *midi); DESCRIPTION
This function will simulate playing the given MIDI, from start to end, to determine how long it takes to play. After calling this function, midi_pos will contain the negative number of beats, and midi_time the length of the midi, in seconds. Note that any currently playing midi is stopped when you call this function. Usually you would call it before play_midi, to get the length of the midi to be played, like in this example: length = get_midi_length(my_midi); play_midi(my_midi); do { pos = midi_time; textprintf_ex(screen, font, 0, 0, c, -1, "%d:%02d / %d:%02d ", pos / 60, pos % 60, length / 60, length % 60); rest(100); } while(pos <= length); RETURN VALUE
Returns the value of midi_time, the length of the midi. SEE ALSO
load_midi(3alleg4), midi_time(3alleg4), midi_pos(3alleg4), exmidi(3alleg4) Allegro version 4.4.2 get_midi_length(3alleg4)
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