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Top Forums Shell Programming and Scripting Formatting File Decryption Output Post 302921386 by Ariean on Thursday 16th of October 2014 04:24:09 PM
Old 10-16-2014
Formatting File Decryption Output

Below is the out put of the decrypt command.

Decrypt Command:
/usr/bin/gpg --yes --batch --output file.xml --decrypt file.xml.gpg

Output:
Code:
gpg: encrypted with 2048-bit RSA key, ID 96301328, created 2014-04-29
      "XYZ <xyz@abc.com>"
gpg: encrypted with 2048-bit ELG-E key, ID ECB614CF, created 2002-02-06
      "PQR <pqr@abc.com>"
gpg: encrypted with 2048-bit ELG-E key, ID 1EB07C50, created 2014-02-20
      "MNP (mnp Data Warehouse file encryption key) <mnp@abc.com>"
gpg: WARNING: message was not integrity protected


My requirement is I need to verify if total 3 keys are present in the encrypted file, the only way i think i know is when i decrypt it and then count the email id's. So how could i get the below email ids from the output i pasted above either by redirecting the output or at the time of decryption itself. After i get this i wanted to go in loop or something to increment a variable to get the count of email id's.

Code:
xyz@abc.com
pqr@abc.com
mnp@abc.com

so far i came up with code but still not getting it correctly

HTML Code:
cat decrypt_output | grep @ decrypt_output | awk -F"<*" '{print $2}'
Code:
xyz@abc.com>"
pqr@abc.com>"
mnp@abc.com>"

appreciate your help.
 

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AMGPGCRYPT(8)						  System Administration Commands					     AMGPGCRYPT(8)

NAME
amgpgcrypt - reference crypt program for Amanda public-key data encryption SYNOPSIS
amgpgcrypt to be called by Amanda only DESCRIPTION
amgpgcrypt calls gpg to perform public-key data encryption on Amanda backup. amgpgcrypt will search for the gpg program in the following directories: /usr/local/bin:/usr/bin:/usr/sbin:/bin:/sbin amgpgcrypt sets GNUPGHOME to $AMANDA_HOME/.gnupg where gpg will look for the gpg keys. amgpgcrypt uses the public key to encrypt the Amanda data and uses the private key to decrypt the Amanda backup data. Thus, passphrase is only required at the time of data restore. KEY AND PASSPHRASE
amgpgcrypt uses the private key to decrypt Amanda backup data. It is very important to store, manage and protect the key and the passphrase properly. Encrypted backup data can only be recovered with the correct key and passphrase. HOW TO CREATE ENCRYPTION KEYS AND PASSPHRASE FOR AMGPGCRYPT
Store the passphrase that you used in following "gpg --gen-key" command inside the home-directory of the AMANDA-user($amanda_user) and protect it with proper permissions: echo my_secret_passphrase > ~$amanda_user/.am_passphrase chown $amanda_user:disk ~$amanda_user/.am_passphrase chmod 700 ~$amanda_user/.am_passphrase Run "gpg --gen-key". Below is an example: $ gpg --gen-key gpg (GnuPG) 1.2.6; Copyright (C) 2004 Free Software Foundation, Inc. This program comes with ABSOLUTELY NO WARRANTY. This is free software, and you are welcome to redistribute it under certain conditions. See the file COPYING for details. Please select what kind of key you want: (1) DSA and ElGamal (default) (2) DSA (sign only) (4) RSA (sign only) Your selection? 1 DSA keypair will have 1024 bits. About to generate a new ELG-E keypair. minimum keysize is 768 bits default keysize is 1024 bits highest suggested keysize is 2048 bits What keysize do you want? (1024) Requested keysize is 1024 bits Please specify how long the key should be valid. 0 = key does not expire (n) = key expires in n days (n)w = key expires in n weeks (n)m = key expires in n months (n)y = key expires in n years Key is valid for? (0) 6m Key expires at Sun 06 Aug 2006 03:51:25 PM PDT Is this correct (y/n)? y You need a User-ID to identify your key; the software constructs the user id from Real Name, Comment and Email Address in this form: "Heinrich Heine (Der Dichter) (heinrichh@duesseldorf.de)" Real name: amandabackup Email address: Comment: gpg keys for amandabackup You selected this USER-ID: "amandabackup (gpg keys for amandabackup)" Change (N)ame, (C)omment, (E)mail or (O)kay/(Q)uit? o You need a Passphrase to protect your secret key. We need to generate a lot of random bytes. It is a good idea to perform some other action (type on the keyboard, move the mouse, utilize the disks) during the prime generation; this gives the random number generator a better chance to gain enough entropy. We need to generate a lot of random bytes. It is a good idea to perform some other action (type on the keyboard, move the mouse, utilize the disks) during the prime generation; this gives the random number generator a better chance to gain enough entropy. public and secret key created and signed. key marked as ultimately trusted. pub 1024D/4417A8CB 2006-02-07 amandabackup (gpg keys for amandabackup) Key fingerprint = 139C 6369 44FC 7F1A 655C E5E9 7EAA 515A 4417 A8CB sub 1024g/8C3A6A78 2006-02-07 [expires: 2006-08-06] FILES
$AMANDA_HOME/.gnupg/pubring.gpg The public key. amgpgcrypt encrypt data with this public key along with the cipher algorithm. $AMANDA_HOME/.gnupg/secring.gpg The private/secret key. It's only needed during amrecover/amrestore. Store and protect it properly during other time. $AMANDA_HOME/.am_passphrase The passphrase. It's only needed during amrecover/amrestore. Store and protect it properly during other time. BUGS
Amanda has problem with gpg mdc(modification detection code) in the binary mode. amgpgcrypt calls gpg with mdc disabled SEE ALSO
amanda(8), amanda.conf(5), amcrypt(8), amrestore(8), gpg(1) The Amanda Wiki: : http://wiki.zmanda.com/ AUTHOR
Kevin Till <kevin.till@zmanda.com> Zmanda, Inc. (http://www.zmanda.com) Amanda 3.3.3 01/10/2013 AMGPGCRYPT(8)
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