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Top Forums UNIX for Dummies Questions & Answers Using sed to replace a range of number Post 302920339 by Scrutinizer on Thursday 9th of October 2014 01:20:18 AM
Old 10-09-2014
/[0-25]/ means 0-2 or 5, so it matches any line with one of the numbers: 0,1,2 or 5 (BTW In your requirements you say greater than 0, but your example would also match 0)

To match the numbers 1-25, you could use: /[1-9][0-5]\{0,1\}/

But to avoid matching "125" of example you need to anchor it front and back, for example:
/^ *[1-9][0-5]\{0,1\} /
Notice the trailing space ...

Another approach is not to use regex, but a numerical comparison. But for this you cannot use sed, which is a streamline editor. Instead you could use awk for example or another scripting language...
Code:
awk '$1>0 && $1 <=25' file


Last edited by Scrutinizer; 10-09-2014 at 02:28 AM..
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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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