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Top Forums UNIX for Dummies Questions & Answers How to replace \ with / in a file? Post 302919823 by bakunin on Saturday 4th of October 2014 06:36:01 AM
Old 10-04-2014
Quote:
Originally Posted by blastit.fr
you can process this output this way for instance
Code:
grep ..... | sed '/\/\//g'

Neither perl nor grep is necessary for this, sed can handle it on its own:

Code:
sed -n '/<regexp-from-grep>/ s/&#x5c;/\//gp'

I hope this helps.

bakunin
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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