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Top Forums Shell Programming and Scripting Replace values in script reading line by line using sed Post 302918877 by RavinderSingh13 on Friday 26th of September 2014 01:16:51 AM
Old 09-26-2014
Quote:
Originally Posted by crimsonengineer
So my output would be a script containing the values in the text file:

I would like my script to repeat for each row in the text file. I think this can be accomplished with sed or awk, but unsure how to piece together the proper commands. Thanks so much.
Hello,

Following may help in same.
Code:
awk '{for(i=1;i<=NF;i++){{if(i%2 != 0){print "for pa in " $i ORS "do" ORS "blah blah" ORS "done\n"} else {print "for pb in " $i ORS "do" ORS "blah blah" ORS "done\n"}}}}' Input_file

Output will be as follows.
Code:
for pa in 14.5
do
blah blah
done
 
for pb in 16.7
do
blah blah
done
 
for pa in 7.8
do
blah blah
done
 
for pb in 9.5
do
blah blah
done
 
for pa in 5.6
do
blah blah
done
 
for pb in 3.6
do
blah blah
done
 
for pa in etc
do
blah blah
done
 
for pb in etc
do
blah blah
done

EDIT: Adding more solutions for same.

Code:
awk '{for(i=1;i<=NF;i++){V=i%2 != 0?(V="pa "):(V="pb "); {print "for " V "in " $i ORS "do" ORS "blah blah" ORS "done\n"}}}'  Input_file
OR
awk '{for(i=1;i<=NF;i++){{if(i%2 != 0){V="pa "} else {V="pb "}; print "for " V "in " $i ORS "do" ORS "blah blah" ORS "done\n"}}}' Input_file

Thanks,
R. Singh

Last edited by RavinderSingh13; 09-26-2014 at 02:32 AM.. Reason: Added 2 more solutions for same
 

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bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
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