Strange, I get :
Hold on, the above is on OSX with BSD find.
On Linux it does not work (just tested it)...
OK ON Linux it is GNU find an there the default regex type is emacs
EDIT: this seems to work on Linux:
Apparently the default "emacs" does not support the brace repetition operator, so it will probably be modeled after an old version of emacs..
So the -regextype option is required to change from the default regex type..
I personally never use regex with find, since it is not standardized..
--
EDIT: With the emacs default of GNU find this works:
But that does not work with BSD find (unless the -E extended regex option is specified)..
Last edited by Scrutinizer; 09-18-2014 at 11:47 AM..
This User Gave Thanks to Scrutinizer For This Post:
I need a perl script which will create an output file after comparing two diff file in a directory path:
/export/home/abc/file1
/export/home/abc/file2
File Format: <IP>TAB<DeviceName><TAB>DESCRIPTIONS
file1:
10.1.2.1.3<tab>abc123def<tab>xyz.mm1.ppp.... (2 Replies)
Hi!
I want to find duplicate files (criteria: file size) in my download folder.
I try it like this:
find /Users/frodo/Downloads \! -type d -exec du {} \; | sort > /Users/frodo/Desktop/duplicates_1.txt;
cut -f 1 /Users/frodo/Desktop/duplicates_1.txt | uniq -d | grep -hif -... (9 Replies)
Hi !
I wonder if anyone can help on this : I have a directory: /xyz that has the following files:
chsLog.107.20130603.gz
chsLog.115.20130603
chsLog.111.20130603.gz
chsLog.107.20130603
chsLog.115.20130603.gz
As you ca see there are two files that are the same but only with a minor... (10 Replies)
Hi champs,
I have one of the requirement, where I need to compare two files line by line and ignore duplicates. Note, I hav files in sorted order.
I have tried using the comm command, but its not working for my scenario.
Input file1
srv1..development..employee..empname,empid,empdesg... (1 Reply)
I have tried the following code and with that i couldnt achieve what i want.
#!/usr/bin/bash
find ./ -type f \( -iname "*.xml" \) | sort -n > fileList
sed -i '/\.\/fileList/d' fileList
NAMEOFTHISFILE=$(echo $0|sed -e 's/\/()$*.^|/\\&/g')
sed -i "/$NAMEOFTHISFILE/d"... (2 Replies)
I would like find and delete old backup files in aix. How would I go about doing this? For example:
server1_1-20-2020
server1_1-21-2020
server1_1-22-2020
server1_1-23-2020
server2_1-20-2020
server2_1-21-2020
server2_1-22-2020
server2_1-23-2020
How would I go about finding and... (3 Replies)
Discussion started by: cokedude
3 Replies
LEARN ABOUT DEBIAN
re_comp
RE_COMP(3) Linux Programmer's Manual RE_COMP(3)NAME
re_comp, re_exec - BSD regex functions
SYNOPSIS
#define _REGEX_RE_COMP
#include <sys/types.h>
#include <regex.h>
char *re_comp(char *regex);
int re_exec(char *string);
DESCRIPTION
re_comp() is used to compile the null-terminated regular expression pointed to by regex. The compiled pattern occupies a static area, the
pattern buffer, which is overwritten by subsequent use of re_comp(). If regex is NULL, no operation is performed and the pattern buffer's
contents are not altered.
re_exec() is used to assess whether the null-terminated string pointed to by string matches the previously compiled regex.
RETURN VALUE
re_comp() returns NULL on successful compilation of regex otherwise it returns a pointer to an appropriate error message.
re_exec() returns 1 for a successful match, zero for failure.
CONFORMING TO
4.3BSD.
NOTES
These functions are obsolete; the functions documented in regcomp(3) should be used instead.
SEE ALSO regcomp(3), regex(7), GNU regex manual
COLOPHON
This page is part of release 3.44 of the Linux man-pages project. A description of the project, and information about reporting bugs, can
be found at http://www.kernel.org/doc/man-pages/.
GNU 1995-07-14 RE_COMP(3)