Replace Special Character With Next Present Byte Post: 302913951

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Top Forums Shell Programming and Scripting Replace Special Character With Next Present Byte Post 302913951 by dineshnak on Thursday 21st of August 2014 06:13:27 AM

08-21-2014

Registered User

Hi,

Thanks for your input. While running the script we are not getting the output and also I need to write the output in a file. Could you please help out on this.

Script

Code:

#!/bin/bash
Input=`cat sample.dat`
echo "$Input"
#while read Input
#do
/usr/xpg4/bin/awk -F '�' '
#{      printf(" Input:%s\nOutput:", $0) }
{       # Print the 1st field unchanged.
        printf("%s", $1)
        # Loop through remaining fields.
        for(i = 2; i <= NF; i++) {
                # Print 3 spaces.
                printf("   ")
                # Get repetition count
                cnt = sprintf("%d", "0x" substr($i, 1, 2)) + 0
                # Print the character to be repeated cnt times.
                chr = substr($i, 3, 1)
#               printf("|cnt=%d,chr=%s|", cnt, chr)
                for(j = 1; j <= cnt; j++)
                        printf("%s", chr)
                # Print the remainder of the field.
                printf("%s", substr($i, 4))
        }
        # Add trailing <newline>.
        print ""
}' Input
#done <output.dat

Sample.dat

Code:

ABC196 7 MIB513AMMOD�07 MIByx66mcp00�06 302619�1A 00005014072605331600�0A 980�32 201407260533160�14 2TRG212 7 98�09 3P PAUTO FMGBN  MIB513AMMOAMERICAN MODER
N INSURANCE302619�40 97871407259787    140724 NBS�19 A2014072520140724

Thanks,
Dines

---------- Post updated at 01:38 AM ---------- Previous update was at 12:38 AM ----------

One more point if it is decimal use the same else convert it to decimal from hexadecimal.

Thanks,
Dines

---------- Post updated at 05:13 AM ---------- Previous update was at 01:38 AM ----------

Hi Don Cragun,

Ran the script but the ouput is not as expected. Please find the code & output below. Facing problem while converting to hexadecimal

Code:

cnt = sprintf("%d", 0x substr($i, 1, 2)) + 0

We changed the input file name the code it's not working
Script

Code:

#!/bin/bash
#Input=`cat /home/dgovk/sample.dat`
#echo "$Input"
#while read Input
#do
/usr/xpg4/bin/awk -F '�' '
#{      printf(" Input:%s\nOutput:", $0) }
{       # Print the 1st field unchanged.
        printf("%s", $1)
        # Loop through remaining fields.
        for(i = 2; i <= NF; i++) {
                # Print 3 spaces.
                printf("   ")
               printf(substr($i, 1, 2))
#               printf("%d", substr($i, 1, 2))
                # Get repetition count
                cnt = sprintf("%d", 0x substr($i, 1, 2)) + 0
                # Print the character to be repeated cnt times.
                chr = substr($i, 3, 1)
#               printf("|cnt=%d,chr=%s|", cnt, chr)
                for(j = 1; j <= cnt; j++)
                        printf("%s", chr)
                # Print the remainder of the field.
                printf("%s", substr($i, 4))
        }
        # Add trailing <newline>.
        print ""
}' Input

Input:

Code:

302619�1A?
ABCD172 2 B10001�0E F�08 DineshG�14 KumarNakka�0E �3C?IN�14?EFGH340

Output:

Code:

302619   ?
ABCD172 2 B10001   F           DineshG                 KumarNakka      ???IN   ??????????????EFGH340

Thanks,
Dinesh

Last edited by rbatte1; 08-21-2014 at 06:11 AM..

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