Some people may suggest calling date twice, but if you do that just before and just after a change in the minute, the two values won't be related the way you want them. (As a close to worst case, that could give you values two hours and 1 minute apart instead of one hour apart.) Try something like:
This was tested using the Korn shell, but will work with any shell that performs POSIX standard shell command substitutions and parameter expansions (including bash and ksh, among others). To see that it works, you'll need to either trace what it is doing or print the results.
It won't work after 11pm, but that doesn't seem to be a problem for you requirements.
This User Gave Thanks to Don Cragun For This Post:
I need to increment a date value through shell script.
Input value consist of start date and end date in DATE format of unix.
For eg.
I need increment a date value of 1/1/09 to 31/12/09 i.e for a whole yr.
The output must look like
1/1/09
2/2/09
.
.
.
31/1/09
.
.
1/2/09
.
28/2/09... (1 Reply)
Hi,
I have a perl script which prints epoch value of date in milliseconds as the output.
My reuirement is that once the output is printed,the day variable shld increment by 1 and when i execute the script for the second time the output shld be for the new day value.
My script looks as... (11 Replies)
Hi,
I have a variable lets say DATA_DATE.
I have to pass some value to this variable in YYYYMMDD format.
lets say today I have passed this variable as :
DATA_DATE=20100107
Then pls help me how to calculate another variable DATA_DATE1 (which is DATA_DATE+1).
The code should work... (3 Replies)
hi Friends,
Today_Dt=`date "+%Y-%m-%d"`
So the Today date is 2010-05-03
I have a file which has date values as below
2010-04-27
2010-04-02
2010-04-18
2010-04-28
2010-04-29
.. (1 Reply)
hi experts,
my requirement is like this i need to develop a shell script to update date part with new incremental date time in file some 'X' which is kept at some server location incrementing every two hours.as i am new to this scripting i need support from u people,thanx in advance (1 Reply)
Hi all,
I need to increment date at run time.
Example:
I need to write a shell script with two parameters.
1. country code like (US,UK, IND.....)
2. Date range from_date to to_date (20070101 to 20070331)
I need to run shell script like this
country_info.sh US 20070101 20070331
... (3 Replies)
Hi All,
I have a file which has hundred of records with fixed number of fields. In each record there is set of 8 characters which represent the duration of that activity. I want to sum up the duration present in all the records for a report. The problem is the duration changes per record so I... (5 Replies)
Hi,
I have parameter file wo_location.prm which has a date variable $last_upd_date= 02032016.
I need to write a unix shell script to find that variable and increment it by 1 day.
The path to the file is root/dir_lc/shared/param/wo_location.prm and the variable is $last_upd_date.
Any... (2 Replies)
hi all,
i would like to increment the date variable i am using
for((i=20190731;i<=20190801;i++))
do
done
after 20190731 it should be 20190801 but this taking as 20190732,20190733....
kindly help me to solve this (3 Replies)
Discussion started by: prathaban
3 Replies
LEARN ABOUT DEBIAN
parse_time
PARSE_TIME(3) BSD Library Functions Manual PARSE_TIME(3)NAME
parse_time, print_time_table, unparse_time, unparse_time_approx, -- parse and unparse time intervals
LIBRARY
The roken library (libroken, -lroken)
SYNOPSIS
#include <parse_time.h>
int
parse_time(const char *timespec, const char *def_unit);
void
print_time_table(FILE *f);
size_t
unparse_time(int seconds, char *buf, size_t len);
size_t
unparse_time_approx(int seconds, char *buf, size_t len);
DESCRIPTION
The parse_time() function converts a the period of time specified in into a number of seconds. The timespec can be any number of <number
unit> pairs separated by comma and whitespace. The number can be negative. Number without explicit units are taken as being def_unit.
The unparse_time() and unparse_time_approx() does the opposite of parse_time(), that is they take a number of seconds and express that as
human readable string. unparse_time produces an exact time, while unparse_time_approx restricts the result to only include one units.
print_time_table() prints a descriptive list of available units on the passed file descriptor.
The possible units include:
second, s
minute, m
hour, h
day
week seven days
month 30 days
year 365 days
Units names can be arbitrarily abbreviated (as long as they are unique).
RETURN VALUES
parse_time() returns the number of seconds that represents the expression in timespec or -1 on error. unparse_time() and
unparse_time_approx() return the number of characters written to buf. if the return value is greater than or equal to the len argument, the
string was too short and some of the printed characters were discarded.
EXAMPLES
#include <stdio.h>
#include <parse_time.h>
int
main(int argc, char **argv)
{
int i;
int result;
char buf[128];
print_time_table(stdout);
for (i = 1; i < argc; i++) {
result = parse_time(argv[i], "second");
if(result == -1) {
fprintf(stderr, "%s: parse error
", argv[i]);
continue;
}
printf("--
");
printf("parse_time = %d
", result);
unparse_time(result, buf, sizeof(buf));
printf("unparse_time = %s
", buf);
unparse_time_approx(result, buf, sizeof(buf));
printf("unparse_time_approx = %s
", buf);
}
return 0;
}
$ ./a.out "1 minute 30 seconds" "90 s" "1 y -1 s"
1 year = 365 days
1 month = 30 days
1 week = 7 days
1 day = 24 hours
1 hour = 60 minutes
1 minute = 60 seconds
1 second
--
parse_time = 90
unparse_time = 1 minute 30 seconds
unparse_time_approx = 1 minute
--
parse_time = 90
unparse_time = 1 minute 30 seconds
unparse_time_approx = 1 minute
--
parse_time = 31535999
unparse_time = 12 months 4 days 23 hours 59 minutes 59 seconds
unparse_time_approx = 12 months
BUGS
Since parse_time() returns -1 on error there is no way to parse "minus one second". Currently "s" at the end of units is ignored. This is a
hack for English plural forms. If these functions are ever localised, this scheme will have to change.
HEIMDAL October 31, 2004 HEIMDAL