I want to change a date from format dd-mmm-yyyy to mm/dd/yyyy. Is there a way to do this with sed or do you have to write a case statement to convert JAN to 01? Thanks (9 Replies)
How to convert the date field from dd/mm/yyyy to yyyy/mm/dd in unix
my script will generate text file which have two fields
one is date and another is name of the server for example this is sample date which I have to sort based on older to newer date the problem is when I found out sort will... (4 Replies)
I have a file which has 100k+ records like this
abc,05-JUN-1974,def,lkj,aaa
def,11-SEP-1975,ghj,dis,dea
I want to convert ex 05-JUN-1974 to 06/05/1974
Please help me with awk script to convert the whole file into MM-DD-YYYY
Thank you! (2 Replies)
Hi all
I have some pipe-separated data in the form:
5/12/2008 00:00:00|31/1/2009 00:00:00|SOMESTUFF|OTHERSTUFF
12/31/2008 00:00:00|15/1/2009 00:00:00|MORESTUFF|REMAININGSTUFF
1/1/1023 00:00:00|16/5/2047 00:00:00|THEREST|YETMORE
I need to zero-pad the single-digit days and months, using... (3 Replies)
My csv has data like this
x,x,3452,2/18/1986,abc
x,g,19711,1/24/1986,abc
i want to replace date in the following format YYYY-mm-dd
how do i convert using awk script ? (8 Replies)
(Attention: Green PHP newbie !)
I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
Hello,
I am writing a script that parses different logs and produces one. In the source files, the date is in DD MM YYYY HH24:MI:SS format. In the output, it should be in DD MON YYY HH24:MI:SS (ie 25 Jan 2010 16:10:10)
To extract the dates, I am using shell substrings, i.e.:
read line
... (4 Replies)
Hi I have a problem with Date format in my code.
1st I am trying to convert today's date to yesterday's using
YESTERDAY3=`perl -e '@y=localtime(time()-86400); printf "%04d/%02d/%02d",$y+1900,$y+1,$y;$y;'`
And once it is done I am trying to using the yesterday date in a grep command to... (3 Replies)
I've seen a lot of posts on this and have tried the following:
echo 1257000000| perl -e '($d,$m,$y)=(localtime(time-86400));$m+=1;$y+=1900;printf "$y/$m/$d\n";'
But I am unable to convert a past Epoch date into a format such as YYYY/MM/DD or MM/DD/YYYY.
I am using bash and don't know... (4 Replies)
I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY.
When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD
file... (3 Replies)
Discussion started by: Roozo
3 Replies
LEARN ABOUT MINIX
sort
SORT(1) General Commands Manual SORT(1)NAME
sort - sort a file of ASCII lines
SYNOPSIS
sort [-bcdfimnru] [-tc] [-o name] [+pos1] [-pos2] file ...
OPTIONS -b Skip leading blanks when making comparisons
-c Check to see if a file is sorted
-d Dictionary order: ignore punctuation
-f Fold upper case onto lower case
-i Ignore nonASCII characters
-m Merge presorted files
-n Numeric sort order
-o Next argument is output file
-r Reverse the sort order
-t Following character is field separator
-u Unique mode (delete duplicate lines)
EXAMPLES
sort -nr file # Sort keys numerically, reversed
sort +2 -4 file # Sort using fields 2 and 3 as key
sort +2 -t: -o out # Field separator is :
sort +.3 -.6 # Characters 3 through 5 form the key
DESCRIPTION
Sort sorts one or more files. If no files are specified, stdin is sorted. Output is written on standard output, unless -o is specified.
The options +pos1 -pos2 use only fields pos1 up to but not including pos2 as the sort key, where a field is a string of characters delim-
ited by spaces and tabs, unless a different field delimiter is specified with -t. Both pos1 and pos2 have the form m.n where m tells the
number of fields and n tells the number of characters. Either m or n may be omitted.
SEE ALSO comm(1), grep(1), uniq(1).
SORT(1)