Shell doesn't do that kind of doublethink. If something's in a variable, it's taken literally (with the exception of glob characters).
Just like in your other thread:
If you explain your actual goal -- not the means you've picked to accomplish it -- we could help you far better!
Your questions suggest you've taken a wrong turn and ended up building a shell-inside-the-shell kind of thing, instead of just using the shell's features in the first place (i.e. building a configuration-file-reader in the shell, instead of just sourcing the file). Not knowing what the shell can do often leads to this kind of catch-22 situation.
But for the record, the xargs utility can understand quotes and print properly grouped lines:
Last edited by Corona688; 07-23-2014 at 06:31 PM..
These 2 Users Gave Thanks to Corona688 For This Post:
This is a totally dumb newbie question, but I have not been able to find t he answer in the BASH book or online.
I am trying pass a double quoted variable to the command line.
variable = "-b \"dc=example,dc=com\""
When I run sh -x the variable comes out as '-b "dc=example,dc=com"' is... (4 Replies)
Hi,
I am generating html code using cshell, but i am having one problem while printing double quotes,
I need to write following code in file. where $var contains list of web address
<a href="$var">$var</a>
So i am using
echo "<a href="$var">$var</a>" > file.html
But with this " in... (4 Replies)
Hi i have to insert the below line into a specific line number of another file
export MBR_CNT_PRCP_TYPE_CODES_DEL="'01','02','04','05','49','55','UNK'"
I have passed the above line to a variable say ins_line. I have used below command to perform the insert
awk 'NR==3{print "'"${ins_line}"'"}1'... (1 Reply)
I need to interpolate a shell variable in a code, i cannot share the exact code so this is an example i made up to describe the situation
What I am trying to do here is try to wrap up the value of a variable in single quotes. This value needs to be passed to another program which would only... (4 Replies)
As the title says I'm running a korn script in attempts to find an exact match in named.conf
finddomain.ksh
#!/bin/ksh
#
echo "********** named.conf ************"
file=/var/named/named.conf
for domain in `cat $1`
do
grep -n '"\$domain "' $file
done
echo "********** thezah.inc... (1 Reply)
Hi All,
OS - Suse 10
ksh --version
version sh (AT&T Research) 93s+ 2008-01-31
I am passing two words within double quotes ("Application Developer") to script as variable, but script is adding two single quotes between two words like ("Application' 'Developer").
below is simple test... (4 Replies)
I am unable to expand the value of entry variable inside the nawk command.
I tried three different nawk command as below but none of them substitute the value of entry variable.
ls *.txt | while IFS='' read -r entry; do
#nawk '/<name>/{A=1;++i} A{print >> ("cmd"i"_"$entry)}... (9 Replies)
Hi got this issue and was wondering if someone could please help out ?
var='." "'
echo $var
." "
I 'll get ." " and not ." with 10 spaces in between "
Thanks (3 Replies)
Discussion started by: stinkefisch
3 Replies
LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)