07-14-2014
Regex: print matched line and exact pattern match
Hi experts,
I have a file with regexes which is used for automatic searches on several files (40+ GB).
To do some postprocessing with the grep result I need the matching line as well as the match itself.
I know that the latter could be achieved with grep's -o option. But I'm not aware of a combined option, i. e. print the match <space> print the matched line or sth like this.
Currently I'm doing this:
zgrep -E -i -f ~/some_patterns.txt <file-list> > result.txt
Based on result.txt some postprocessing takes place. Maybe the extraction of the exact match should be part of the postprocessing?
Alternatively I could switch to an awk construction as well if this would meet my needs better.
TIA & best regards
Stephan
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ZGREP(1) General Commands Manual ZGREP(1)
NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)
ZGREP(1)