I understand how to use a variable in a sed command, but for the life of me I can't get the output into a variable.
I'm making a general function to replace part of a filename with a different string, so:
>>myscript this that
would change:
this_file001.txt to that_file001.txt and... (11 Replies)
I m trying to pass variable to sed.
export var=140920060731
sed -e '/$var/d' file
but no luch so far..? any body has any idea abt it
Is there any way to pass variable to SED?
Thanks ,
Manish (2 Replies)
hi,
dataParse(){
line="$@"
name="cat /etc/passwd | grep "$line": | cut -f6 -d':'"
eval $name > sam.txt 2>&1
sudo -u $line sed -n 's/data-1/&/p' $name/test.xml >> sam1.txt
}
Here i getting the homedir of the accounts and is set in
name variable.which returns "/home/raju" which i... (3 Replies)
:confused: Is it possible to send a variable to a sed or cut command? I have a test script as below:
counter=1
while read line
do
# Test the file
printf "$line" > temp$counter
pref=$(cut c1-2000 $temp$counter | sed 's///g' | sed 's|.*PutTime\(.*)Origin.*|\1|')
printf" let... (5 Replies)
Hi, I'm a bit of sed n00b here.
My issue is as follows:
I'm trying to pass a variable to sed so that all instances of this variable (in a text file) will be replaced with nothing. However, the value of this variable will always be a folder location e.g. "C:\Program Files\Folder1"
I... (5 Replies)
Dear All,
I want to print a file.
First I tried with this
sed '2q;d' filename
it worked. But when i put following it is not working
x=2;
sed '$xq;d' filename
Would any one suggest how to pass the variable? (7 Replies)
Hi guys,
I wanted to pass a variable to the sed command which tells which line to be deleted.
a=2;
echo $a;
sed '$ad' c.out
it is throwing an error.
sed: 0602-403 "$a"d is not a recognized function.
I even tried "$a" and \$a.. but it is of no use.
Can you please correct me... (6 Replies)
Hello All,
I am trying to embed variable in sed command to fetch a portion of record between two pattern.
This command is not working ...any suggestion on this how to place the variable in sed command to find a portion .
I am using Sun OS (Solaris).
Thanks
JM (1 Reply)
Here is my code
#!/bin/bash
username=gnowicki
sed '$s/$/ $username/' < sshd_config 1 <> sshd_config
what this is supposed to do is take the name gnowicki and put it at the end of the last line of the sshd_config and it works except not using the variable, if I put the name "gnowicki" where... (2 Replies)
Hi
I have below sed to search and print particular line that matches in file and prints it, which is actually working fine as expected.
sed -n "/^2012-11-19 23:*/p" filename
but if I replace date with the variable it seems it's not recognizing it and throwing out error
v="2012-11-19"... (4 Replies)
Discussion started by: manas_ranjan
4 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)