07-10-2014
Quote:
Originally Posted by
srkmish
I dint get you.
By
ssh -v -v ... Corona688 wants you to increase the verbosity of the command output. It's easier for debugging.
9 More Discussions You Might Find Interesting
1. Red Hat
I am trying to set up ssh/scp to be able to login in w/o using a password. The man pages for ssh and ssh-keygen explain how to do this.
So, using "rsa1" style, I created the public and private keys by way of ssh-keygen, then added the contents of "$HOME/.ssh/identity.pub" to a newly created... (6 Replies)
Discussion started by: mcrouch_2003
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2. Solaris
Hi Gurus,
Wanted to know if there is a way to enable passwordless login between specific users in a Solaris (5.9)server.
I copied the public key of first user into the $HOME/.ssh/authorized_keys file of the second user. But it didn't work out.
Note - Am talking about users in the same... (9 Replies)
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3. Solaris
Hi GUYS,
Me have 2 servers, eg:: A & B
id_dsa.pub key of B had been put in authorized_keys of A & Vice versa
Passwordless login going from A to B.
But while connecting from B to A ,its asking password
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4. HP-UX
Greetings!
I am trying to perform a passwordless SSH login from a HPUX 11.31 client to a HPUX 11.31 server. Whenever I do a "ssh -l root serverA" from the client, I am prompted for a password. Giving the password, I am able to successfully login. However I am trying to accomplish a... (9 Replies)
Discussion started by: Rob Sandifer
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5. UNIX for Advanced & Expert Users
Hi,
I have two users login on my HPUX i.e user1 and user2.
Inorder to switch from user1 to user2 without password I generated key pair using keygen command for user id user1 and copied the its public key to the .ssh/authorized_keys file of user2.
ssh-keygen -b 2048 -t rsa
This... (5 Replies)
Discussion started by: mohtashims
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6. Solaris
This is Solaris 10 and sorce+destination are non root user. Somehow it is broke and I am not able to fix it. Already checked permissions on both servers and authorized_keys entry of destination is same as id_rsa.pub of source server. I can not regenerate keys on source server because I do not know,... (0 Replies)
Discussion started by: solaris_1977
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7. Shell Programming and Scripting
Hi,
I am in the process FTPing some of my report files from my production server to another FTP server through batch/Shell Script.
This is working fine with the password less authentication.
Once i place all my report files in the ftp server the end users need to download ... (3 Replies)
Discussion started by: Showdown
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8. Shell Programming and Scripting
how can i use an expect script to do a passwordless ssh login and run a script on a bunch of remote hosts? I do not want to use public key authentication as this would require me to setup the keys on the clients etc.... (2 Replies)
Discussion started by: tdubb123
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9. Windows & DOS: Issues & Discussions
Hi,
I am a newbie and has been given a task to connect to a windows server from a linux server (using putty of course; for file transfer) that too passwordless.
Searching through google I found "ssh-keygen" but this also couldn't work because as I tried ssh <username>@<windowsServerIP>, it says... (5 Replies)
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LEARN ABOUT CENTOS
shell-quote
SHELL-QUOTE(1) User Contributed Perl Documentation SHELL-QUOTE(1)
NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS
--debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.16.3 2010-06-11 SHELL-QUOTE(1)