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Full Discussion: Unable to swap values
Top Forums Shell Programming and Scripting Unable to swap values Post 302907803 by Chubler_XL on Tuesday 1st of July 2014 11:18:43 PM
Old 07-02-2014
You could be deceiving yourself with the first echo statement which is printing your current directory using the pwd executable not the value of $pwd

Remember to use [code] and [/code] tags around your posted code to keep the format nice:

Code:
#!/bin/bash
pwd=`cat 1.ini | grep -w PWD | cut -d'=' -f2` 
echo "the value is $pwd"

pwd2=`cat 2.ini | grep -w PWD | cut -d'=' -f2` 
echo "the value of pwd2 is $pwd2"

if [[ "$pwd" == "$pwd2" ]]
then
  echo both are same
else
  temp_pwd=$pwd2
  pwd2=$pwd
  pwd=$temp_pwd

  echo ------------------
  echo the value is pwd is $pwd
  echo the value is pwd2 is $pwd2
  echo the value is temp_pwd is $temp_pwd
fi

 

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NAME

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SYNTAX

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DESCRIPTION

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FILES

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