06-25-2014
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
I understand how to use a variable in a sed command, but for the life of me I can't get the output into a variable.
I'm making a general function to replace part of a filename with a different string, so:
>>myscript this that
would change:
this_file001.txt to that_file001.txt and... (11 Replies)
Discussion started by: donflamenco
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2. Shell Programming and Scripting
Hi All,
Hope someone can advise here as I have been struggling to find a syntax that works here. I have tried a stack of combination I have seed in the forums but I think because I have needed to use "" and `` in the statments another method is found.
I am reading in lines with the following... (1 Reply)
Discussion started by: nkwilliams
1 Replies
3. Shell Programming and Scripting
Hi all,
Hope someone can help me out here.
I have this BASH script (see below)
My problem lies with the variable path.
The output of the command find will give me several fields. The 9th field is the path. I want to captured that and the I want to filter this to a specific level.
The... (6 Replies)
Discussion started by: Cowardly
6 Replies
4. Shell Programming and Scripting
hi i want to find the size of a folder and assign it to a variable and then compare if it is greater than 1 gb.
i am doin this script, but it is throwing error....
#!/bin/ksh
cd . | du -s | size = awk '{print $1}'
if size >= 112000
then
echo size high
fi
ERROR : (4 Replies)
Discussion started by: Nithz
4 Replies
5. Shell Programming and Scripting
Hi,
I have a problem with passing a echo output into a variable in bash
file='1990.tar'
NAME='echo $file | cut -d '.' -f1';
echo $NAME
the result is
echo $file | cut -d . -f1
however with this one,#!/bin/bash
file='1990.tar'
echo $file | cut -d '.' -f1
the result is what I... (2 Replies)
Discussion started by: 1988PF
2 Replies
6. Shell Programming and Scripting
I have a variable $WORDS that contains a string
Then i want to use sed to break it up.
echo $WORDS | sed 's// /g'
I tried setting this as a variable by doing
WORDS2=`echo $WORDS | sed 's// /g'`
But when i do this it does not return me to the prompt properly
ie.
jmpprd-v1>
jmpprd-v1>... (4 Replies)
Discussion started by: nitrobass24
4 Replies
7. Shell Programming and Scripting
Hello all,
I wrote this command line for some calculation on my given input files based on another input file which is a txt file.
while read BAM REGION; do samtools view $BAM $REGION | awk '{if ($2==0) print $0}' | wc -l >>log.txt; echo "$REGION"; done >> log.txt <regions.txt
It takes... (4 Replies)
Discussion started by: @man
4 Replies
8. Shell Programming and Scripting
Hi Experts,
I am trying to get system output to capture inside awk , but not working:
Please advise if this is possible :
I am trying something like this but not working, the output is coming wrong:
echo "" | awk '{d=system ("date") ; print "Current date is:" , d }'
Thanks, (5 Replies)
Discussion started by: rveri
5 Replies
9. Shell Programming and Scripting
Hello,
I've been trying to find the answer to this with Google and trying to browse the forums, but I haven't been able to come up with anything. If this has already been answered, please link me to the thread as I can't find it.
I've been asked to write a script that pulls a list of our CPE... (51 Replies)
Discussion started by: rwalker
51 Replies
10. UNIX for Beginners Questions & Answers
Hi,
I am generating a YAML file from a hosts file, but am having trouble saving it to a new file.
hosts file
127.0.0.1 localhost
192.168.1.2 host1
192.168.1.3 host2
192.168.1.4 host3
192.168.1.5 host4
YAML file
$ echo 'host_entries:' && awk '{printf " %s:\n ip:... (3 Replies)
Discussion started by: sand1234
3 Replies
EVAL(3) 1 EVAL(3)
eval - Evaluate a string as PHP code
SYNOPSIS
mixed eval (string $code)
DESCRIPTION
Evaluates the given $code as PHP.
Caution
The eval(3) language construct is very dangerous because it allows execution of arbitrary PHP code. Its use thus is discouraged.
If you have carefully verified that there is no other option than to use this construct, pay special attention not to pass any user
provided data into it without properly validating it beforehand.
PARAMETERS
o $code
- Valid PHP code to be evaluated. The code mustn't be wrapped in opening and closing PHP tags, i.e. 'echo "Hi!";' must be passed
instead of '<? echo "Hi!"; >'. It is still possible to leave and reenter PHP mode though using the appropriate PHP tags, e.g.
'echo "In PHP mode!"; ?>In HTML mode!<? echo "Back in PHP mode!";'. Apart from that the passed code must be valid PHP. This
includes that all statements must be properly terminated using a semicolon. 'echo "Hi!"' for example will cause a parse error,
whereas 'echo "Hi!";' will work. A return statement will immediately terminate the evaluation of the code. The code will be exe-
cuted in the scope of the code calling eval(3). Thus any variables defined or changed in the eval(3) call will remain visible
after it terminates.
RETURN VALUES
eval(3) returns NULL unless return is called in the evaluated code, in which case the value passed to return is returned. If there is a
parse error in the evaluated code, eval(3) returns FALSE and execution of the following code continues normally. It is not possible to
catch a parse error in eval(3) using set_error_handler(3).
EXAMPLES
Example #1
eval(3) example - simple text merge
<?php
$string = 'cup';
$name = 'coffee';
$str = 'This is a $string with my $name in it.';
echo $str. "
";
eval("$str = "$str";");
echo $str. "
";
?>
The above example will output:
This is a $string with my $name in it.
This is a cup with my coffee in it.
NOTES
Note
Because this is a language construct and not a function, it cannot be called using variable functions.
Tip
As with anything that outputs its result directly to the browser, the output-control functions can be used to capture the output of
this function, and save it in a string (for example).
Note
In case of a fatal error in the evaluated code, the whole script exits.
SEE ALSO
call_user_func(3).
PHP Documentation Group EVAL(3)