If testing something like this (contents of test.sh)
(This code is not inside a loop.)
The thing is that when executing this code with ksh (RHEL 6.5) there's no error message from the shell.
But when executing with bash there's an error message when case has to evaluate a condition with break. When executed with ksh or sh, there's no error message.
As far as I know, break it has sense only when there's a loop. But since there's no error message for ksh and sh it looks like the behaviour for case is different from bash.
case syntax without break works fine in ksh and sh, with no error messages. Same with bash, as expected.
Any thoughts about this behaviour?
This is probably the same behaviour in ksh-AIX but I couldn't access a machine to test it right now.
The standards say:
Quote:
The break utility shall exit from the smallest enclosing for, while, or until loop, if any; or from
the nth enclosing loop if n is specified.
It looks like bash writes a warning message to stderr (but does not affect the exit status) in this case while ksh behaves as specified by the standards (silently ignoring the fact that your code is issuing a break when there is no enclosing loop).
This User Gave Thanks to Don Cragun For This Post:
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