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Top Forums Shell Programming and Scripting Sed: printing lines AFTER pattern matching EXCLUDING the line containing the pattern Post 302904501 by rbatte1 on Wednesday 4th of June 2014 10:54:31 AM
Old 06-04-2014
Does your server support the -A flag on grep? That might be a neater solution:-
Code:
grep -A10 pattern  file

Maybe I've missed the point. If you want all lines after a certain point, perhaps you could use grep to get the record number and then tail to get you the output you need:-
Code:
#!/bin/ksh

grep -n pattern  file|tr ":" " "|read line xxx       # Get the interesting line number
wc -l file | read total xxx                          # Get total lines
((readrecs=$total-$line))                            # Work out how many lines from end to read
tail -$readrecs   file


Do either of these help?


Robin
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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