Hi to all.
I'm trying to sort this with the Unix command sort.
user1:12345678:3.5:2.5:8:1:2:3
user2:12345679:4.5:3.5:8:1:3:2
user3:12345687:5.5:2.5:6:1:3:2
user4:12345670:5.5:2.5:5:3:2:1
user5:12345671:2.5:5.5:7:2:3:1
I need to get this:
user3:12345687:5.5:2.5:6:1:3:2... (7 Replies)
Hello all -
I am to this forum and fairly new in learning unix and finding some difficulty in preparing a small shell script. I am trying to make script to sort all the files given by user as input (either the exact full name of the file or say the files matching the criteria like all files... (3 Replies)
sort --random-sort
The full command is
path=`find /testdir -maxdepth 1 -mindepth 1 -type d | ***Some sort of sort function*** | head -1`
I have a list I want to randomly sort. It works fine in ubuntu but on a 'osx lion' sort dosen't have the --random-sort option.
I don't want to... (5 Replies)
Input file:
100%ABC2 3.44E-12 USA
A2M%H02579 0E0 UK
100%ABC2 5.34E-8 UK
100%ABC2 3.25E-12 USA
A2M%H02579 5E-45 UK
Output file:
100%ABC2 3.44E-12 USA
100%ABC2 3.25E-12 USA
100%ABC2 5.34E-8 UK
A2M%H02579 0E0 UK
A2M%H02579 5E-45 UK
Code try:
sort -k1,1 -g -k2 -r input.txt... (2 Replies)
Hi Experts,
I have a filelist collected from another server , now want to sort the output using date/time stamp filed.
- Filed 6, 7,8 are showing the date/time/stamp.
Here is the input:
#----------------------------------------------------------------------
-rw------- 1 root ... (3 Replies)
Hi,
I have a file where data is pipe separated.First i want to sort the file content by date . Then i want to pick up the records based on the first column which should be unique and not have duplicates.
NYSE|yyyrrrddd|toronto|isin|ticker|2013-05-15... (2 Replies)
Hi,
Could anyone kindly show me a link or explain the difference between
sort -n -k2 -k3 & sort -n -k2,3
Also, if I like to remove the row with repetition at both $2 and $3, Can I safely use
sort -u -k2 -k3
Example;
100 20 30
100 20 30
So, both $2 and $3 are same and I... (2 Replies)
How to sort the following output based on lowest to highest BE?
The following sort does not work.
$ sort -t. -k1,1n -k2,2n bfd.txt
BE31.116 0s 0s DOWN DAMP
BE31.116 0s 0s DOWN DAMP
BE31.117 0s 0s ... (7 Replies)
Discussion started by: sand1234
7 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)