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Full Discussion: Independent column sorting
Top Forums UNIX for Dummies Questions & Answers Independent column sorting Post 302896401 by Akshay Hegde on Monday 7th of April 2014 11:48:20 AM
Old 04-07-2014
Try :

Code:
#!/bin/ksh

# Loop through files
for file in *.csv; do

# counting fields from first line and assuming fields in remaining lines are equal to first line
field=$(awk -F, 'NR==1{print NF;exit}' $file)

# Creating arguments here
for(( i=1; i<=$field; i++ )); do
  [ $i -eq 1 ] && arg="<(cut -d, -f$i $file | sort)" || arg="$arg  <(cut -d, -f$i $file | sort)"
done

# Final command to execute
final_cmd="paste $arg | tr -s '\t' ','"

# writing to new file
eval $final_cmd >"output_new_$file"

done

Code:
$ cat a.csv 
1,5,7
3,4,9
2,6,8

$ ksh tester

$ ls *.csv -1
a.csv
output_new_a.csv

$ cat output_new_a.csv 
1,4,7
2,5,8
3,6,9

Last edited by Akshay Hegde; 04-07-2014 at 12:54 PM..
This User Gave Thanks to Akshay Hegde For This Post:
A-V
 

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NAME

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