Hi,
I'm using bash and ksh93 compatible derivatives.
In a recent getopts experience, I found myself spending far too much
time on this little problem. I hope someone can help...
So here's the deal.
I want to build have a command line interface that accepts either zero,
one, or... (4 Replies)
Hi
I executed the code
for file in `ls pdb*.ent`
do
new_name=`echo $file | sed 's/^pdb//;s/.ent/.txt/'`
mv $file $new_name
done
Its giving error at ' ls pdb*.ent' argument list too long
i have around 150000 entries
please help
Thank you (6 Replies)
I have a wrote a script which consits of the below line.. Below of this script I'm getting this error "ksh: /usr/bin/ls: arg list too long"
The line is
log_file_time=`ssh -i $HOME/.ssh/id_rsa -q $i ls -lrt /bp/karthik/test/data/log/$abc*|tail -1|awk '{print $8}'`
And $abc alias is as "p |... (1 Reply)
Dear Experts,
I have a list of 10K files in a directory. I am not able to execute any commands lile ls -lrt, awk, sed, mv, etc........
I wanna execute below command and get the output. How can I achieve it?? Pls help.
root# awk -F'|' '$1 == 1' file_20120710* | wc -l
/bin/awk: Argument list... (2 Replies)
Hi,
i am having some trouble with the below command, can some one suggest me the better way to do it.
grep -l 'ReturnCode=1' `find $Log -newer /tmp/Failed.tmp -print | xargs ls -ld | egrep SUB | egrep -ve 'MTP' -ve 'ABC' -ve 'DEF' -ve 'JKL' -ve 'XYZ' | awk '{print $9}'` > $Home1
Its... (2 Replies)
Hi I am using find command --
find "directory1" -type f | xargs -i mv {} "directory2"
to avoid above argument list too long problem.
But, issue i am facing is directory1 is having subdirectories due to this i am facing directory traversal problem as i dont want to traverse subdirectories... (9 Replies)
Hi all,
I am using GNU sed (named gsed under macports) in OSX. I have a directory with a series of files named pool_01.jpg through pool_78802.jpg. I am trying to use this command to rename the files to their checksum + extension.
md5sum * | gsed -e 's/\(*\) \(.*\(\..*\)\)$/mv -v \2 \1\3/e'
... (3 Replies)
Hi Team,
Here's the situation.
I have approximately 300000 to 500000 jpg files in /appl/abcd/work_dir
mv /appl/abcd/work_dir /appl/abcd/process_dir
The above move command will work if the jpg files count is close to 50000 (not sure). If the count is less this mv command holds good. But if... (14 Replies)
Is there a way I can specify the name of a list as an argument to a shell script and then use the values of that list name in the script?
I need to do this WITHOUT using case statements.
Something like this:
check.sh list1
#!/bin/bash
list1="www.amazon.com www.google.com"... (9 Replies)
Discussion started by: gctaylor
9 Replies
LEARN ABOUT FREEBSD
ssh-copy-id
SSH-COPY-ID(1) BSD General Commands Manual SSH-COPY-ID(1)NAME
ssh-copy-id -- copy public keys to a remote host
SYNOPSIS
ssh-copy-id [-lv] [-i keyfile] [-o option] [-p port] [user@]hostname
DESCRIPTION
The ssh-copy-id utility copies public keys to a remote host's ~/.ssh/authorized_keys file (creating the file and directory, if required).
The following options are available:
-i file
Copy the public key contained in file. This option can be specified multiple times and can be combined with the -l option. If a
private key is specified and a public key is found then the public key will be used.
-l Copy the keys currently held by ssh-agent(1). This is the default if the -i option was not specified.
-o ssh-option
Pass this option directly to ssh(1). This option can be specified multiple times.
-p port
Connect to the specified port on the remote host instead of the default.
-v Pass -v to ssh(1).
The remaining arguments are a list of remote hosts to connect to, each one optionally qualified by a user name.
EXIT STATUS
The ssh-copy-id utility exits 0 on success, and >0 if an error occurs.
EXAMPLES
To send a specific key to multiple hosts:
$ ssh-copy-id -i /path/to/keyfile.pub user@host1 user@host2 user@host3
HISTORY
The ssh-copy-id utility was written by Eitan Adler <eadler@FreeBSD.org> as a drop-in replacement for an existing utility included with
OpenSSH.
BSD February 28, 2014 BSD
03-10-2014
[Solved] Argument list with awk
