Login or Register to Ask a Question and Join Our Community

Sponsored Content
Full Discussion: [Solved] Awk: count occurrence of each character for every field
Top Forums UNIX for Dummies Questions & Answers [Solved] Awk: count occurrence of each character for every field Post 302890981 by SriniShoo on Monday 3rd of March 2014 02:07:48 AM
Old 03-03-2014
Try the below
Code:
awk 'BEGIN{FS = "|"; OFS = "|"}
  {for(i = 1; i <= NF; i++) {a[i " " $i]++}}
  END {for(x in a) {print x "=" a[x]}}' <INPUT_FILE> | awk '{if(a[$1] == "") {a[$1] = $1 "|" $2} else {a[$1] = (a[$1] "|" $2)}; if(max < $1) {max = $1}}
    END {for(i = 1; i <= max; i++) {print a[i]}}'

This User Gave Thanks to SriniShoo For This Post:
beca123456
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Count number of occurences of a character in a field defined by the character in another field

Hello, I have a text file with n lines in the following format (9 column fields): Example: contig00012 149606 G C 49 68 60 18 c$cccccacccccccccc^c I need to count the number of lower-case and upper-case occurences in column 9, respectively, of the... (3 Replies)
Discussion started by: s052866
3 Replies

2. Shell Programming and Scripting

[Solved] Sed/awk print between patterns the first occurrence

Guys, I am trying the following: i have a log file of a webbap which logs in the following pattern: 2011-08-14 21:10:04,535 blablabla ERROR blablabla bla bla bla bla 2011-08-14 21:10:04,535 blablabla ERROR blablabla bla bla bla ... (6 Replies)
Discussion started by: ppolianidis
6 Replies

3. UNIX for Dummies Questions & Answers

[Solved] Count amount of times of appearing of character before a word?

Hello Is there a way to calculate how many times a particular symbol appeared in a string before a particular word. Desktop/Myfiles/pet/dog/puppy So, I want to count number of occurence of"/" in this directory before the word dog lets say. Cheers, Bob (3 Replies)
Discussion started by: FUTURE_EINSTEIN
3 Replies

4. Shell Programming and Scripting

awk - count character count of fields

Hello All, I got a requirement when I was working with a file. Say the file has unloads of data from a table in the form 1|121|asda|434|thesi|2012|05|24| 1|343|unit|09|best|2012|11|5| I was put into a scenario where I need the field count in all the lines in that file. It was simply... (6 Replies)
Discussion started by: PikK45
6 Replies

5. Shell Programming and Scripting

[solved]awk count occurences in time window

Input File Time, KeyStation 00:00:00,000;KS_1 00:00:01,000;KS_1 00:00:02,000;KS_1 00:00:03,000;KS_1 00:00:04,000;KS_1 00:00:05,000;KS_1 00:00:06,000;KS_1 00:01:01,000;KS_1 00:01:02,000;KS_1 00:01:03,000;KS_1 00:01:04,000;KS_1 00:01:05,000;KS_1 00:01:06,000;KS_1 01:00:01,000;KS_1... (0 Replies)
Discussion started by: Calypso
0 Replies

6. Shell Programming and Scripting

Count occurrence of string in a column using awk

Hi, I want to count the occurrences of strings in a column and display as in example below: Input: get1 345 789 098 get2 567 982 090 fet4 777 610 632 get1 800 544 230 get1 600 788 451 get2 892 321 243 get1 673 111 235 fet3 789 220 278 fet4 768 222 341 output: 4 get1 345 789... (7 Replies)
Discussion started by: aydj
7 Replies

7. Programming

awk to count occurrence of strings and loop for multiple columns

Hi all, If i would like to process a file input as below: col1 col2 col3 ...col100 1 A C E A ... 3 D E G A 5 T T A A 6 D C A G how can i perform a for loop to count the occurences of letters in each column? (just like uniq -c ) in every column. on top of that, i would also like... (8 Replies)
Discussion started by: iling14
8 Replies

8. UNIX for Dummies Questions & Answers

Count occurrence of string (based on type) in a column using awk

Hello, I have a table that looks like what is shown below: AA BB CC XY PQ RS AA BB CC XY RS I would like the total counts depending on the set they belong to: if search pattern is in {AA, BB, CC} --> count them as Type1 | wc -l (3 Replies)
Discussion started by: Gussifinknottle
3 Replies

9. Shell Programming and Scripting

awk to count condition in field

I am trying to confirm the counts from another code and tried the below awk, but the syntax is incorrect. Basically, outputting the counts of each condition in $8. Thank you :) awk '$8==/TYPE=snp/ /TYPE=ins/ /TYPE=del/ {count++} END{print count}'... (6 Replies)
Discussion started by: cmccabe
6 Replies

10. Shell Programming and Scripting

awk or other way to find out number of occurrence of 7th character

Hi all, I am looking for to filter out based on 7th character and list the number of occurrence based on the 7th character if p , d , o or m 1. if 7th character is p , Output should be: p_hosts = N 2. if 7th character is d , Output should be: d_hosts = N 3. if 7th character is o , Output... (10 Replies)
Discussion started by: rveri
10 Replies

LEARN ABOUT DEBIAN

bup-margin

bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME

       bup-margin - figure out your deduplication safety margin

SYNOPSIS

       bup margin [options...]

DESCRIPTION

       bup margin  iterates  through  all  objects  in	your  bup repository, calculating the largest number of prefix bits shared between any two
       entries.  This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.

       For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45.  That  means  a  46-bit
       hash  would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
       its first 46 bits.

       The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects.  Since SHA-1 hashes have 160 bits,
       that  leaves 115 bits of margin.  Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
       with far fewer objects.

       If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see	if
       you're getting dangerously close to 160 bits.

OPTIONS

       --predict
	      Guess  the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
	      from the guess.  This is potentially useful for tuning an interpolation search algorithm.

       --ignore-midx
	      don't use .midx files, use only .idx files.  This is only really useful when used with --predict.

EXAMPLE

	      $ bup margin
	      Reading indexes: 100.00% (1612581/1612581), done.
	      40
	      40 matching prefix bits
	      1.94 bits per doubling
	      120 bits (61.86 doublings) remaining
	      4.19338e+18 times larger is possible

	      Everyone on earth could have 625878182 data sets
	      like yours, all in one repository, and we would
	      expect 1 object collision.

	      $ bup margin --predict
	      PackIdxList: using 1 index.
	      Reading indexes: 100.00% (1612581/1612581), done.
	      915 of 1612581 (0.057%)

SEE ALSO

       bup-midx(1), bup-save(1)

BUP

       Part of the bup(1) suite.

AUTHORS

       Avery Pennarun <apenwarr@gmail.com>.

Bup unknown-															     bup-margin(1)
All times are GMT -4. The time now is 02:55 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy